Whakaoti i te sqrt{x+x}=x

$$\sqrt { x + x } = x$$

Whakaoti mō x

$$x=2$$

$$x=0$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{x+x}\right)^{2}=x^{2}$$

Pahekotia te x me x, ka 2x.

$$\left(\sqrt{2x}\right)^{2}=x^{2}$$

Tātaihia te \sqrt{2x} mā te pū o 2, kia riro ko 2x.

$$2x=x^{2}$$

Tangohia te x^{2} mai i ngā taha e rua.

$$2x-x^{2}=0$$

Tauwehea te x.

$$x\left(2-x\right)=0$$

Hei kimi otinga whārite, me whakaoti te x=0 me te 2-x=0.

$$x=0 x=2$$

Whakakapia te 0 mō te x i te whārite \sqrt{x+x}=x.

$$\sqrt{0+0}=0$$

Whakarūnātia. Ko te uara x=0 kua ngata te whārite.

$$0=0$$

Whakakapia te 2 mō te x i te whārite \sqrt{x+x}=x.

$$\sqrt{2+2}=2$$

Whakarūnātia. Ko te uara x=2 kua ngata te whārite.

$$2=2$$

Rārangihia ngā rongoā katoa o \sqrt{x+x}=x.

$$x=0 x=2$$