Whakaoti i te sqrt{x+3}=sqrt{1-x}

$$\sqrt { x + 3 } = \sqrt { 1 - x }$$

Whakaoti mō x

$$x=-1$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{x+3}\right)^{2}=\left(\sqrt{1-x}\right)^{2}$$

Tātaihia te \sqrt{x+3} mā te pū o 2, kia riro ko x+3.

$$x+3=\left(\sqrt{1-x}\right)^{2}$$

Tātaihia te \sqrt{1-x} mā te pū o 2, kia riro ko 1-x.

$$x+3=1-x$$

Me tāpiri te x ki ngā taha e rua.

$$x+3+x=1$$

Pahekotia te x me x, ka 2x.

$$2x+3=1$$

Tangohia te 3 mai i ngā taha e rua.

$$2x=1-3$$

Tangohia te 3 i te 1, ka -2.

$$2x=-2$$

Whakawehea ngā taha e rua ki te 2.

$$x=\frac{-2}{2}$$

Whakawehea te -2 ki te 2, kia riro ko -1.

$$x=-1$$

Whakakapia te -1 mō te x i te whārite \sqrt{x+3}=\sqrt{1-x}.

$$\sqrt{-1+3}=\sqrt{1-\left(-1\right)}$$

Whakarūnātia. Ko te uara x=-1 kua ngata te whārite.

$$2^{\frac{1}{2}}=2^{\frac{1}{2}}$$

Ko te whārite \sqrt{x+3}=\sqrt{1-x} he rongoā ahurei.

$$x=-1$$