Whakaoti i te sqrt{9x-28}=sqrt{5x}

$$\sqrt { 9 x - 28 } = \sqrt { 5 x }$$

Whakaoti mō x

$$x=7$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{9x-28}\right)^{2}=\left(\sqrt{5x}\right)^{2}$$

Tātaihia te \sqrt{9x-28} mā te pū o 2, kia riro ko 9x-28.

$$9x-28=\left(\sqrt{5x}\right)^{2}$$

Tātaihia te \sqrt{5x} mā te pū o 2, kia riro ko 5x.

$$9x-28=5x$$

Tangohia te 5x mai i ngā taha e rua.

$$9x-28-5x=0$$

Pahekotia te 9x me -5x, ka 4x.

$$4x-28=0$$

Me tāpiri te 28 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$4x=28$$

Whakawehea ngā taha e rua ki te 4.

$$x=\frac{28}{4}$$

Whakawehea te 28 ki te 4, kia riro ko 7.

$$x=7$$

Whakakapia te 7 mō te x i te whārite \sqrt{9x-28}=\sqrt{5x}.

$$\sqrt{9\times 7-28}=\sqrt{5\times 7}$$

Whakarūnātia. Ko te uara x=7 kua ngata te whārite.

$$35^{\frac{1}{2}}=35^{\frac{1}{2}}$$

Ko te whārite \sqrt{9x-28}=\sqrt{5x} he rongoā ahurei.

$$x=7$$