Whakaoti i te sqrt{9v-15}=sqrt{7v-1}

$$\sqrt { 9 v - 15 } = \sqrt { 7 v - 1 }$$

Whakaoti mō v

$$v=7$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{9v-15}\right)^{2}=\left(\sqrt{7v-1}\right)^{2}$$

Tātaihia te \sqrt{9v-15} mā te pū o 2, kia riro ko 9v-15.

$$9v-15=\left(\sqrt{7v-1}\right)^{2}$$

Tātaihia te \sqrt{7v-1} mā te pū o 2, kia riro ko 7v-1.

$$9v-15=7v-1$$

Tangohia te 7v mai i ngā taha e rua.

$$9v-15-7v=-1$$

Pahekotia te 9v me -7v, ka 2v.

$$2v-15=-1$$

Me tāpiri te 15 ki ngā taha e rua.

$$2v=-1+15$$

Tāpirihia te -1 ki te 15, ka 14.

$$2v=14$$

Whakawehea ngā taha e rua ki te 2.

$$v=\frac{14}{2}$$

Whakawehea te 14 ki te 2, kia riro ko 7.

$$v=7$$

Whakakapia te 7 mō te v i te whārite \sqrt{9v-15}=\sqrt{7v-1}.

$$\sqrt{9\times 7-15}=\sqrt{7\times 7-1}$$

Whakarūnātia. Ko te uara v=7 kua ngata te whārite.

$$4\times 3^{\frac{1}{2}}=4\times 3^{\frac{1}{2}}$$

Ko te whārite \sqrt{9v-15}=\sqrt{7v-1} he rongoā ahurei.

$$v=7$$