Whakaoti i te sqrt{9+4sqrt{36-2sqrt{6^2+8^2}}}=?

$$\sqrt { 9 + 4 \sqrt { 36 - 2 \sqrt { 6 ^ { 2 } + 8 ^ { 2 } } } } = ?$$

Aromātai

$$5$$

Ngā Upane Otinga

Tātaihia te 6 mā te pū o 2, kia riro ko 36.

$$\sqrt{9+4\sqrt{36-2\sqrt{36+8^{2}}}}$$

Tātaihia te 8 mā te pū o 2, kia riro ko 64.

$$\sqrt{9+4\sqrt{36-2\sqrt{36+64}}}$$

Tāpirihia te 36 ki te 64, ka 100.

$$\sqrt{9+4\sqrt{36-2\sqrt{100}}}$$

Tātaitia te pūtakerua o 100 kia tae ki 10.

$$\sqrt{9+4\sqrt{36-2\times 10}}$$

Whakareatia te 2 ki te 10, ka 20.

$$\sqrt{9+4\sqrt{36-20}}$$

Tangohia te 20 i te 36, ka 16.

$$\sqrt{9+4\sqrt{16}}$$

Tātaitia te pūtakerua o 16 kia tae ki 4.

$$\sqrt{9+4\times 4}$$

Whakareatia te 4 ki te 4, ka 16.

$$\sqrt{9+16}$$

Tāpirihia te 9 ki te 16, ka 25.

$$\sqrt{25}$$

Tātaitia te pūtakerua o 25 kia tae ki 5.

$$5$$

Tauwehe

$$5$$