Whakaoti i te sqrt{8y+4}=sqrt{7y+7}

$$\sqrt { 8 y + 4 } = \sqrt { 7 y + 7 }$$

Whakaoti mō y

$$y=3$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{8y+4}\right)^{2}=\left(\sqrt{7y+7}\right)^{2}$$

Tātaihia te \sqrt{8y+4} mā te pū o 2, kia riro ko 8y+4.

$$8y+4=\left(\sqrt{7y+7}\right)^{2}$$

Tātaihia te \sqrt{7y+7} mā te pū o 2, kia riro ko 7y+7.

$$8y+4=7y+7$$

Tangohia te 7y mai i ngā taha e rua.

$$8y+4-7y=7$$

Pahekotia te 8y me -7y, ka y.

$$y+4=7$$

Tangohia te 4 mai i ngā taha e rua.

$$y=7-4$$

Tangohia te 4 i te 7, ka 3.

$$y=3$$

Whakakapia te 3 mō te y i te whārite \sqrt{8y+4}=\sqrt{7y+7}.

$$\sqrt{8\times 3+4}=\sqrt{7\times 3+7}$$

Whakarūnātia. Ko te uara y=3 kua ngata te whārite.

$$2\times 7^{\frac{1}{2}}=2\times 7^{\frac{1}{2}}$$

Ko te whārite \sqrt{8y+4}=\sqrt{7y+7} he rongoā ahurei.

$$y=3$$