Whakaoti i te sqrt{6a-5}-sqrt{4a+8}=0

$$\sqrt { 6 a - 5 } - \sqrt { 4 a + 8 } = 0$$

Whakaoti mō a

$$a = \frac{13}{2} = 6\frac{1}{2} = 6.5$$

Ngā Upane Otinga

Me tango -\sqrt{4a+8} mai i ngā taha e rua o te whārite.

$$\sqrt{6a-5}=\sqrt{4a+8}$$

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{6a-5}\right)^{2}=\left(\sqrt{4a+8}\right)^{2}$$

Tātaihia te \sqrt{6a-5} mā te pū o 2, kia riro ko 6a-5.

$$6a-5=\left(\sqrt{4a+8}\right)^{2}$$

Tātaihia te \sqrt{4a+8} mā te pū o 2, kia riro ko 4a+8.

$$6a-5=4a+8$$

Tangohia te 4a mai i ngā taha e rua.

$$6a-5-4a=8$$

Pahekotia te 6a me -4a, ka 2a.

$$2a-5=8$$

Me tāpiri te 5 ki ngā taha e rua.

$$2a=8+5$$

Tāpirihia te 8 ki te 5, ka 13.

$$2a=13$$

Whakawehea ngā taha e rua ki te 2.

$$a=\frac{13}{2}$$

Whakakapia te \frac{13}{2} mō te a i te whārite \sqrt{6a-5}-\sqrt{4a+8}=0.

$$\sqrt{6\times \frac{13}{2}-5}-\sqrt{4\times \frac{13}{2}+8}=0$$

Whakarūnātia. Ko te uara a=\frac{13}{2} kua ngata te whārite.

$$0=0$$

Ko te whārite \sqrt{6a-5}=\sqrt{4a+8} he rongoā ahurei.

$$a=\frac{13}{2}$$