Whakaoti i te sqrt{4x-8}=sqrt{x+7}

$$\sqrt { 4 x - 8 } = \sqrt { x + 7 }$$

Whakaoti mō x

$$x=5$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{4x-8}\right)^{2}=\left(\sqrt{x+7}\right)^{2}$$

Tātaihia te \sqrt{4x-8} mā te pū o 2, kia riro ko 4x-8.

$$4x-8=\left(\sqrt{x+7}\right)^{2}$$

Tātaihia te \sqrt{x+7} mā te pū o 2, kia riro ko x+7.

$$4x-8=x+7$$

Tangohia te x mai i ngā taha e rua.

$$4x-8-x=7$$

Pahekotia te 4x me -x, ka 3x.

$$3x-8=7$$

Me tāpiri te 8 ki ngā taha e rua.

$$3x=7+8$$

Tāpirihia te 7 ki te 8, ka 15.

$$3x=15$$

Whakawehea ngā taha e rua ki te 3.

$$x=\frac{15}{3}$$

Whakawehea te 15 ki te 3, kia riro ko 5.

$$x=5$$

Whakakapia te 5 mō te x i te whārite \sqrt{4x-8}=\sqrt{x+7}.

$$\sqrt{4\times 5-8}=\sqrt{5+7}$$

Whakarūnātia. Ko te uara x=5 kua ngata te whārite.

$$2\times 3^{\frac{1}{2}}=2\times 3^{\frac{1}{2}}$$

Ko te whārite \sqrt{4x-8}=\sqrt{x+7} he rongoā ahurei.

$$x=5$$