Whakaoti i te sqrt{3^2+sqrt{49}}+(1/4)^-1+(2^2)^3

$$\sqrt { 3 ^ { 2 } + \sqrt { 49 } } + ( \frac { 1 } { 4 } ) ^ { - 1 } + ( 2 ^ { 2 } ) ^ { 3 }$$

Aromātai

$$72$$

Ngā Upane Otinga

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 2 me te 3 kia riro ai te 6.

$$\sqrt{3^{2}+\sqrt{49}}+\left(\frac{1}{4}\right)^{-1}+2^{6}$$

Tātaihia te 3 mā te pū o 2, kia riro ko 9.

$$\sqrt{9+\sqrt{49}}+\left(\frac{1}{4}\right)^{-1}+2^{6}$$

Tātaitia te pūtakerua o 49 kia tae ki 7.

$$\sqrt{9+7}+\left(\frac{1}{4}\right)^{-1}+2^{6}$$

Tāpirihia te 9 ki te 7, ka 16.

$$\sqrt{16}+\left(\frac{1}{4}\right)^{-1}+2^{6}$$

Tātaitia te pūtakerua o 16 kia tae ki 4.

$$4+\left(\frac{1}{4}\right)^{-1}+2^{6}$$

Tātaihia te \frac{1}{4} mā te pū o -1, kia riro ko 4.

$$4+4+2^{6}$$

Tāpirihia te 4 ki te 4, ka 8.

$$8+2^{6}$$

Tātaihia te 2 mā te pū o 6, kia riro ko 64.

$$8+64$$

Tāpirihia te 8 ki te 64, ka 72.

$$72$$

Tauwehe

$$2^{3}\times 3^{2}$$