Whakaoti i te sqrt{25}+4*2^1+36:(3-2)^4+5-2^2=

$$\sqrt { 25 } + 4 \cdot 2 ^ { 1 } + 36 : ( 3 - 2 ) ^ { 4 } + 5 - 2 ^ { 2 } =$$

Aromātai

$$50$$

Ngā Upane Otinga

Tātaitia te pūtakerua o 25 kia tae ki 5.

$$5+4\times 2^{1}+\frac{36}{\left(3-2\right)^{4}}+5-2^{2}$$

Tātaihia te 2 mā te pū o 1, kia riro ko 2.

$$5+4\times 2+\frac{36}{\left(3-2\right)^{4}}+5-2^{2}$$

Whakareatia te 4 ki te 2, ka 8.

$$5+8+\frac{36}{\left(3-2\right)^{4}}+5-2^{2}$$

Tāpirihia te 5 ki te 8, ka 13.

$$13+\frac{36}{\left(3-2\right)^{4}}+5-2^{2}$$

Tangohia te 2 i te 3, ka 1.

$$13+\frac{36}{1^{4}}+5-2^{2}$$

Tātaihia te 1 mā te pū o 4, kia riro ko 1.

$$13+\frac{36}{1}+5-2^{2}$$

Ka whakawehea he tau ki te tahi, hua ai ko ia anō.

$$13+36+5-2^{2}$$

Tāpirihia te 13 ki te 36, ka 49.

$$49+5-2^{2}$$

Tāpirihia te 49 ki te 5, ka 54.

$$54-2^{2}$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$54-4$$

Tangohia te 4 i te 54, ka 50.

$$50$$

Tauwehe

$$2\times 5^{2}$$