Whakaoti i te sqrt{2x-3}=y

$$\sqrt { 2 x - 3 } = y$$

Whakaoti mō x

$$x=\frac{y^{2}+3}{2}$$

$$y\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Pūruatia ngā taha e rua o te whārite.

$$2x-3=y^{2}$$

Me tāpiri 3 ki ngā taha e rua o te whārite.

$$2x-3-\left(-3\right)=y^{2}-\left(-3\right)$$

Mā te tango i te -3 i a ia ake anō ka toe ko te 0.

$$2x=y^{2}-\left(-3\right)$$

Tango -3 mai i y^{2}.

$$2x=y^{2}+3$$

Whakawehea ngā taha e rua ki te 2.

$$\frac{2x}{2}=\frac{y^{2}+3}{2}$$

Mā te whakawehe ki te 2 ka wetekia te whakareanga ki te 2.

$$x=\frac{y^{2}+3}{2}$$

Whakaoti mō x (complex solution)

$$x=\frac{y^{2}+3}{2}$$

$$arg(y)<\pi \text{ or }y=0$$

Whakaoti mō y (complex solution)

$$y=\sqrt{2x-3}$$

Whakaoti mō y

$$y=\sqrt{2x-3}$$

$$x\geq \frac{3}{2}$$