Whakaoti i te sqrt{2x-1}=sqrt{x+2}

$$\sqrt { 2 x - 1 } = \sqrt { x + 2 }$$

Whakaoti mō x

$$x=3$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{2x-1}\right)^{2}=\left(\sqrt{x+2}\right)^{2}$$

Tātaihia te \sqrt{2x-1} mā te pū o 2, kia riro ko 2x-1.

$$2x-1=\left(\sqrt{x+2}\right)^{2}$$

Tātaihia te \sqrt{x+2} mā te pū o 2, kia riro ko x+2.

$$2x-1=x+2$$

Tangohia te x mai i ngā taha e rua.

$$2x-1-x=2$$

Pahekotia te 2x me -x, ka x.

$$x-1=2$$

Me tāpiri te 1 ki ngā taha e rua.

$$x=2+1$$

Tāpirihia te 2 ki te 1, ka 3.

$$x=3$$

Whakakapia te 3 mō te x i te whārite \sqrt{2x-1}=\sqrt{x+2}.

$$\sqrt{2\times 3-1}=\sqrt{3+2}$$

Whakarūnātia. Ko te uara x=3 kua ngata te whārite.

$$5^{\frac{1}{2}}=5^{\frac{1}{2}}$$

Ko te whārite \sqrt{2x-1}=\sqrt{x+2} he rongoā ahurei.

$$x=3$$