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\sqrt{2x+7}=x-4
Me tango 4 mai i ngā taha e rua o te whārite.
\left(\sqrt{2x+7}\right)^{2}=\left(x-4\right)^{2}
Pūruatia ngā taha e rua o te whārite.
2x+7=\left(x-4\right)^{2}
Tātaihia te \sqrt{2x+7} mā te pū o 2, kia riro ko 2x+7.
2x+7=x^{2}-8x+16
Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(x-4\right)^{2}.
2x+7-x^{2}=-8x+16
Tangohia te x^{2} mai i ngā taha e rua.
2x+7-x^{2}+8x=16
Me tāpiri te 8x ki ngā taha e rua.
10x+7-x^{2}=16
Pahekotia te 2x me 8x, ka 10x.
10x+7-x^{2}-16=0
Tangohia te 16 mai i ngā taha e rua.
10x-9-x^{2}=0
Tangohia te 16 i te 7, ka -9.
-x^{2}+10x-9=0
Hurinahatia te pūrau ki te āhua tānga ngahuru. Whakaraupapahia ngā kīanga tau mai i te pū teitei rawa ki te mea iti rawa.
a+b=10 ab=-\left(-9\right)=9
Hei whakaoti i te whārite, whakatauwehea te taha mauī mā te whakarōpū. Tuatahi, me tuhi anō te taha mauī hei -x^{2}+ax+bx-9. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.
1,9 3,3
I te mea kua tōrunga te ab, he ōrite te tohu o a me b. I te mea kua tōrunga te a+b, he tōrunga hoki a a me b. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua 9.
1+9=10 3+3=6
Tātaihia te tapeke mō ia takirua.
a=9 b=1
Ko te otinga te takirua ka hoatu i te tapeke 10.
\left(-x^{2}+9x\right)+\left(x-9\right)
Tuhia anō te -x^{2}+10x-9 hei \left(-x^{2}+9x\right)+\left(x-9\right).
-x\left(x-9\right)+x-9
Whakatauwehea atu -x i te -x^{2}+9x.
\left(x-9\right)\left(-x+1\right)
Whakatauwehea atu te kīanga pātahi x-9 mā te whakamahi i te āhuatanga tātai tohatoha.
x=9 x=1
Hei kimi otinga whārite, me whakaoti te x-9=0 me te -x+1=0.
\sqrt{2\times 9+7}+4=9
Whakakapia te 9 mō te x i te whārite \sqrt{2x+7}+4=x.
9=9
Whakarūnātia. Ko te uara x=9 kua ngata te whārite.
\sqrt{2\times 1+7}+4=1
Whakakapia te 1 mō te x i te whārite \sqrt{2x+7}+4=x.
7=1
Whakarūnātia. Ko te uara x=1 kāore e ngata ana ki te whārite.
x=9
Ko te whārite \sqrt{2x+7}=x-4 he rongoā ahurei.