Whakaoti i te sqrt{2u+3}=sqrt{-2u-1}

$$\sqrt { 2 u + 3 } = \sqrt { - 2 u - 1 }$$

Whakaoti mō u

$$u=-1$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{2u+3}\right)^{2}=\left(\sqrt{-2u-1}\right)^{2}$$

Tātaihia te \sqrt{2u+3} mā te pū o 2, kia riro ko 2u+3.

$$2u+3=\left(\sqrt{-2u-1}\right)^{2}$$

Tātaihia te \sqrt{-2u-1} mā te pū o 2, kia riro ko -2u-1.

$$2u+3=-2u-1$$

Me tāpiri te 2u ki ngā taha e rua.

$$2u+3+2u=-1$$

Pahekotia te 2u me 2u, ka 4u.

$$4u+3=-1$$

Tangohia te 3 mai i ngā taha e rua.

$$4u=-1-3$$

Tangohia te 3 i te -1, ka -4.

$$4u=-4$$

Whakawehea ngā taha e rua ki te 4.

$$u=\frac{-4}{4}$$

Whakawehea te -4 ki te 4, kia riro ko -1.

$$u=-1$$

Whakakapia te -1 mō te u i te whārite \sqrt{2u+3}=\sqrt{-2u-1}.

$$\sqrt{2\left(-1\right)+3}=\sqrt{-2\left(-1\right)-1}$$

Whakarūnātia. Ko te uara u=-1 kua ngata te whārite.

$$1=1$$

Ko te whārite \sqrt{2u+3}=\sqrt{-2u-1} he rongoā ahurei.

$$u=-1$$