Whakaoti i te sqrt{2}x+2(sqrt{2}+2)=sqrt{2}

$$\sqrt { 2 } x + 2 ( \sqrt { 2 } + 2 ) = \sqrt { 2 }$$

Whakaoti mō x

$$x=-2\sqrt{2}-1\approx -3.828427125$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te \sqrt{2}+2.

$$\sqrt{2}x+2\sqrt{2}+4=\sqrt{2}$$

Tangohia te 2\sqrt{2} mai i ngā taha e rua.

$$\sqrt{2}x+4=\sqrt{2}-2\sqrt{2}$$

Pahekotia te \sqrt{2} me -2\sqrt{2}, ka -\sqrt{2}.

$$\sqrt{2}x+4=-\sqrt{2}$$

Tangohia te 4 mai i ngā taha e rua.

$$\sqrt{2}x=-\sqrt{2}-4$$

Whakawehea ngā taha e rua ki te \sqrt{2}.

$$\frac{\sqrt{2}x}{\sqrt{2}}=\frac{-\sqrt{2}-4}{\sqrt{2}}$$

Mā te whakawehe ki te \sqrt{2} ka wetekia te whakareanga ki te \sqrt{2}.

$$x=\frac{-\sqrt{2}-4}{\sqrt{2}}$$

Whakawehe -\sqrt{2}-4 ki te \sqrt{2}.

$$x=-2\sqrt{2}-1$$