Whakaoti i te sqrt{2^2+9^2+15}+sqrt{25}-sqrt{36}=

$$\sqrt { 2 ^ { 2 } + 9 ^ { 2 } + 15 } + \sqrt { 25 } - \sqrt { 36 } =$$

Aromātai

$$9$$

Ngā Upane Otinga

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$\sqrt{4+9^{2}+15}+\sqrt{25}-\sqrt{36}$$

Tātaihia te 9 mā te pū o 2, kia riro ko 81.

$$\sqrt{4+81+15}+\sqrt{25}-\sqrt{36}$$

Tāpirihia te 4 ki te 81, ka 85.

$$\sqrt{85+15}+\sqrt{25}-\sqrt{36}$$

Tāpirihia te 85 ki te 15, ka 100.

$$\sqrt{100}+\sqrt{25}-\sqrt{36}$$

Tātaitia te pūtakerua o 100 kia tae ki 10.

$$10+\sqrt{25}-\sqrt{36}$$

Tātaitia te pūtakerua o 25 kia tae ki 5.

$$10+5-\sqrt{36}$$

Tāpirihia te 10 ki te 5, ka 15.

$$15-\sqrt{36}$$

Tātaitia te pūtakerua o 36 kia tae ki 6.

$$15-6$$

Tangohia te 6 i te 15, ka 9.

$$9$$

Tauwehe

$$3^{2}$$