Whakaoti i te sqrt{16-2x}=2sqrt{x-8}

$$\sqrt { 16 - 2 x } = 2 \sqrt { x - 8 }$$

Whakaoti mō x

$$x=8$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{16-2x}\right)^{2}=\left(2\sqrt{x-8}\right)^{2}$$

Tātaihia te \sqrt{16-2x} mā te pū o 2, kia riro ko 16-2x.

$$16-2x=\left(2\sqrt{x-8}\right)^{2}$$

Whakarohaina te \left(2\sqrt{x-8}\right)^{2}.

$$16-2x=2^{2}\left(\sqrt{x-8}\right)^{2}$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$16-2x=4\left(\sqrt{x-8}\right)^{2}$$

Tātaihia te \sqrt{x-8} mā te pū o 2, kia riro ko x-8.

$$16-2x=4\left(x-8\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te x-8.

$$16-2x=4x-32$$

Tangohia te 4x mai i ngā taha e rua.

$$16-2x-4x=-32$$

Pahekotia te -2x me -4x, ka -6x.

$$16-6x=-32$$

Tangohia te 16 mai i ngā taha e rua.

$$-6x=-32-16$$

Tangohia te 16 i te -32, ka -48.

$$-6x=-48$$

Whakawehea ngā taha e rua ki te -6.

$$x=\frac{-48}{-6}$$

Whakawehea te -48 ki te -6, kia riro ko 8.

$$x=8$$

Whakakapia te 8 mō te x i te whārite \sqrt{16-2x}=2\sqrt{x-8}.

$$\sqrt{16-2\times 8}=2\sqrt{8-8}$$

Whakarūnātia. Ko te uara x=8 kua ngata te whārite.

$$0=0$$

Ko te whārite \sqrt{16-2x}=2\sqrt{x-8} he rongoā ahurei.

$$x=8$$