Whakaoti i te sqrt{-2x-4}=sqrt{-9+3x}

$$\sqrt { - 2 x - 4 } = \sqrt { - 9 + 3 x }$$

Whakaoti mō x (complex solution)

$$x=1$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{-2x-4}\right)^{2}=\left(\sqrt{-9+3x}\right)^{2}$$

Tātaihia te \sqrt{-2x-4} mā te pū o 2, kia riro ko -2x-4.

$$-2x-4=\left(\sqrt{-9+3x}\right)^{2}$$

Tātaihia te \sqrt{-9+3x} mā te pū o 2, kia riro ko -9+3x.

$$-2x-4=-9+3x$$

Tangohia te 3x mai i ngā taha e rua.

$$-2x-4-3x=-9$$

Pahekotia te -2x me -3x, ka -5x.

$$-5x-4=-9$$

Me tāpiri te 4 ki ngā taha e rua.

$$-5x=-9+4$$

Tāpirihia te -9 ki te 4, ka -5.

$$-5x=-5$$

Whakawehea ngā taha e rua ki te -5.

$$x=\frac{-5}{-5}$$

Whakawehea te -5 ki te -5, kia riro ko 1.

$$x=1$$

Whakakapia te 1 mō te x i te whārite \sqrt{-2x-4}=\sqrt{-9+3x}.

$$\sqrt{-2-4}=\sqrt{-9+3\times 1}$$

Whakarūnātia. Ko te uara x=1 kua ngata te whārite.

$$i\times 6^{\frac{1}{2}}=i\times 6^{\frac{1}{2}}$$

Ko te whārite \sqrt{-2x-4}=\sqrt{3x-9} he rongoā ahurei.

$$x=1$$