Whakaoti i te sqrt{(6sqrt{5})^2+(3sqrt{5})^2}

$$\sqrt { ( 6 \sqrt { 5 } ) ^ { 2 } + ( 3 \sqrt { 5 } ) ^ { 2 } }$$

Aromātai

$$15$$

Ngā Upane Otinga

Whakarohaina te \left(6\sqrt{5}\right)^{2}.

$$\sqrt{6^{2}\left(\sqrt{5}\right)^{2}+\left(3\sqrt{5}\right)^{2}}$$

Tātaihia te 6 mā te pū o 2, kia riro ko 36.

$$\sqrt{36\left(\sqrt{5}\right)^{2}+\left(3\sqrt{5}\right)^{2}}$$

Ko te pūrua o \sqrt{5} ko 5.

$$\sqrt{36\times 5+\left(3\sqrt{5}\right)^{2}}$$

Whakareatia te 36 ki te 5, ka 180.

$$\sqrt{180+\left(3\sqrt{5}\right)^{2}}$$

Whakarohaina te \left(3\sqrt{5}\right)^{2}.

$$\sqrt{180+3^{2}\left(\sqrt{5}\right)^{2}}$$

Tātaihia te 3 mā te pū o 2, kia riro ko 9.

$$\sqrt{180+9\left(\sqrt{5}\right)^{2}}$$

Ko te pūrua o \sqrt{5} ko 5.

$$\sqrt{180+9\times 5}$$

Whakareatia te 9 ki te 5, ka 45.

$$\sqrt{180+45}$$

Tāpirihia te 180 ki te 45, ka 225.

$$\sqrt{225}$$

Tātaitia te pūtakerua o 225 kia tae ki 15.

$$15$$

Tauwehe

$$3\times 5$$