Whakaoti i te sqrt{4/3*(1/2)^2*(10/7-3/7)^2*frac{3}{2}+(frac{1}{2}-frac{1}{4})*6-[(frac{1}{4})^2:(frac{1}{4}:4)]^3}

$$\sqrt { \frac { 4 } { 3 } \times ( \frac { 1 } { 2 } ) ^ { 2 } \times ( \frac { 10 } { 7 } - \frac { 3 } { 7 } ) ^ { 2 } \times \frac { 3 } { 2 } + ( \frac { 1 } { 2 } - \frac { 1 } { 4 } ) \times 6 - [ ( \frac { 1 } { 4 } ) ^ { 2 } : ( \frac { 1 } { 4 } : 4 ) ] ^ { 3 } }$$

Aromātai

$$1$$

Ngā Upane Otinga

Tātaihia te \frac{1}{2} mā te pū o 2, kia riro ko \frac{1}{4}.

$$\sqrt{\frac{4}{3}\times \frac{1}{4}\left(\frac{10}{7}-\frac{3}{7}\right)^{2}\times \frac{3}{2}+\left(\frac{1}{2}-\frac{1}{4}\right)\times 6-\left(\frac{\left(\frac{1}{4}\right)^{2}}{\frac{\frac{1}{4}}{4}}\right)^{3}}$$

Whakareatia te \frac{4}{3} ki te \frac{1}{4}, ka \frac{1}{3}.

$$\sqrt{\frac{1}{3}\left(\frac{10}{7}-\frac{3}{7}\right)^{2}\times \frac{3}{2}+\left(\frac{1}{2}-\frac{1}{4}\right)\times 6-\left(\frac{\left(\frac{1}{4}\right)^{2}}{\frac{\frac{1}{4}}{4}}\right)^{3}}$$

Tangohia te \frac{3}{7} i te \frac{10}{7}, ka 1.

$$\sqrt{\frac{1}{3}\times 1^{2}\times \frac{3}{2}+\left(\frac{1}{2}-\frac{1}{4}\right)\times 6-\left(\frac{\left(\frac{1}{4}\right)^{2}}{\frac{\frac{1}{4}}{4}}\right)^{3}}$$

Tātaihia te 1 mā te pū o 2, kia riro ko 1.

$$\sqrt{\frac{1}{3}\times 1\times \frac{3}{2}+\left(\frac{1}{2}-\frac{1}{4}\right)\times 6-\left(\frac{\left(\frac{1}{4}\right)^{2}}{\frac{\frac{1}{4}}{4}}\right)^{3}}$$

Whakareatia te \frac{1}{3} ki te 1, ka \frac{1}{3}.

$$\sqrt{\frac{1}{3}\times \frac{3}{2}+\left(\frac{1}{2}-\frac{1}{4}\right)\times 6-\left(\frac{\left(\frac{1}{4}\right)^{2}}{\frac{\frac{1}{4}}{4}}\right)^{3}}$$

Whakareatia te \frac{1}{3} ki te \frac{3}{2}, ka \frac{1}{2}.

$$\sqrt{\frac{1}{2}+\left(\frac{1}{2}-\frac{1}{4}\right)\times 6-\left(\frac{\left(\frac{1}{4}\right)^{2}}{\frac{\frac{1}{4}}{4}}\right)^{3}}$$

Tangohia te \frac{1}{4} i te \frac{1}{2}, ka \frac{1}{4}.

$$\sqrt{\frac{1}{2}+\frac{1}{4}\times 6-\left(\frac{\left(\frac{1}{4}\right)^{2}}{\frac{\frac{1}{4}}{4}}\right)^{3}}$$

Whakareatia te \frac{1}{4} ki te 6, ka \frac{3}{2}.

$$\sqrt{\frac{1}{2}+\frac{3}{2}-\left(\frac{\left(\frac{1}{4}\right)^{2}}{\frac{\frac{1}{4}}{4}}\right)^{3}}$$

Tāpirihia te \frac{1}{2} ki te \frac{3}{2}, ka 2.

$$\sqrt{2-\left(\frac{\left(\frac{1}{4}\right)^{2}}{\frac{\frac{1}{4}}{4}}\right)^{3}}$$

Tātaihia te \frac{1}{4} mā te pū o 2, kia riro ko \frac{1}{16}.

$$\sqrt{2-\left(\frac{\frac{1}{16}}{\frac{\frac{1}{4}}{4}}\right)^{3}}$$

Tuhia te \frac{\frac{1}{4}}{4} hei hautanga kotahi.

$$\sqrt{2-\left(\frac{\frac{1}{16}}{\frac{1}{4\times 4}}\right)^{3}}$$

Whakareatia te 4 ki te 4, ka 16.

$$\sqrt{2-\left(\frac{\frac{1}{16}}{\frac{1}{16}}\right)^{3}}$$

Whakawehea te \frac{1}{16} ki te \frac{1}{16}, kia riro ko 1.

$$\sqrt{2-1^{3}}$$

Tātaihia te 1 mā te pū o 3, kia riro ko 1.

$$\sqrt{2-1}$$

Tangohia te 1 i te 2, ka 1.

$$\sqrt{1}$$

Tātaitia te pūtakerua o 1 kia tae ki 1.

$$1$$

Tauwehe

$$1$$