Whakaoti i te sqrt{{[(2/3+1/2)-1/6]^2}^3+1-(2/3+frac{7}{6}+frac{2}{12})+[15*(frac{1}{3}+frac{1}{5})]^2}

$$\sqrt { \{ [ ( \frac { 2 } { 3 } + \frac { 1 } { 2 } ) - \frac { 1 } { 6 } ] ^ { 2 } \} ^ { 3 } + 1 - ( \frac { 2 } { 3 } + \frac { 7 } { 6 } + \frac { 2 } { 12 } ) + [ 15 \times ( \frac { 1 } { 3 } + \frac { 1 } { 5 } ) ] ^ { 2 } }$$

Aromātai

$$8$$

Ngā Upane Otinga

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 2 me te 3 kia riro ai te 6.

$$\sqrt{\left(\frac{2}{3}+\frac{1}{2}-\frac{1}{6}\right)^{6}+1-\left(\frac{2}{3}+\frac{7}{6}+\frac{2}{12}\right)+\left(15\left(\frac{1}{3}+\frac{1}{5}\right)\right)^{2}}$$

Tāpirihia te \frac{2}{3} ki te \frac{1}{2}, ka \frac{7}{6}.

$$\sqrt{\left(\frac{7}{6}-\frac{1}{6}\right)^{6}+1-\left(\frac{2}{3}+\frac{7}{6}+\frac{2}{12}\right)+\left(15\left(\frac{1}{3}+\frac{1}{5}\right)\right)^{2}}$$

Tangohia te \frac{1}{6} i te \frac{7}{6}, ka 1.

$$\sqrt{1^{6}+1-\left(\frac{2}{3}+\frac{7}{6}+\frac{2}{12}\right)+\left(15\left(\frac{1}{3}+\frac{1}{5}\right)\right)^{2}}$$

Tātaihia te 1 mā te pū o 6, kia riro ko 1.

$$\sqrt{1+1-\left(\frac{2}{3}+\frac{7}{6}+\frac{2}{12}\right)+\left(15\left(\frac{1}{3}+\frac{1}{5}\right)\right)^{2}}$$

Tāpirihia te 1 ki te 1, ka 2.

$$\sqrt{2-\left(\frac{2}{3}+\frac{7}{6}+\frac{2}{12}\right)+\left(15\left(\frac{1}{3}+\frac{1}{5}\right)\right)^{2}}$$

Tāpirihia te \frac{2}{3} ki te \frac{7}{6}, ka \frac{11}{6}.

$$\sqrt{2-\left(\frac{11}{6}+\frac{2}{12}\right)+\left(15\left(\frac{1}{3}+\frac{1}{5}\right)\right)^{2}}$$

Whakahekea te hautanga \frac{2}{12} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$\sqrt{2-\left(\frac{11}{6}+\frac{1}{6}\right)+\left(15\left(\frac{1}{3}+\frac{1}{5}\right)\right)^{2}}$$

Tāpirihia te \frac{11}{6} ki te \frac{1}{6}, ka 2.

$$\sqrt{2-2+\left(15\left(\frac{1}{3}+\frac{1}{5}\right)\right)^{2}}$$

Tangohia te 2 i te 2, ka 0.

$$\sqrt{0+\left(15\left(\frac{1}{3}+\frac{1}{5}\right)\right)^{2}}$$

Tāpirihia te \frac{1}{3} ki te \frac{1}{5}, ka \frac{8}{15}.

$$\sqrt{0+\left(15\times \frac{8}{15}\right)^{2}}$$

Whakareatia te 15 ki te \frac{8}{15}, ka 8.

$$\sqrt{0+8^{2}}$$

Tātaihia te 8 mā te pū o 2, kia riro ko 64.

$$\sqrt{0+64}$$

Tāpirihia te 0 ki te 64, ka 64.

$$\sqrt{64}$$

Tātaitia te pūtakerua o 64 kia tae ki 8.

$$8$$

Tauwehe

$$2^{3}$$