Whakaoti i te sqrt{[(21/2-1/6+02)*9]-11/4}=

$$\sqrt { [ ( 2 \frac { 1 } { 2 } - \frac { 1 } { 6 } + 02 ) \cdot 9 ] - \frac { 11 } { 4 } } =$$

Aromātai

$$\frac{\sqrt{73}}{2}\approx 4.272001873$$

Ngā Upane Otinga

Whakareatia te 2 ki te 2, ka 4.

$$\sqrt{\left(\frac{4+1}{2}-\frac{1}{6}+0\times 2\right)\times 9-\frac{11}{4}}$$

Tāpirihia te 4 ki te 1, ka 5.

$$\sqrt{\left(\frac{5}{2}-\frac{1}{6}+0\times 2\right)\times 9-\frac{11}{4}}$$

Ko te maha noa iti rawa atu o 2 me 6 ko 6. Me tahuri \frac{5}{2} me \frac{1}{6} ki te hautau me te tautūnga 6.

$$\sqrt{\left(\frac{15}{6}-\frac{1}{6}+0\times 2\right)\times 9-\frac{11}{4}}$$

Tā te mea he rite te tauraro o \frac{15}{6} me \frac{1}{6}, me tango rāua mā te tango i ō raua taurunga.

$$\sqrt{\left(\frac{15-1}{6}+0\times 2\right)\times 9-\frac{11}{4}}$$

Tangohia te 1 i te 15, ka 14.

$$\sqrt{\left(\frac{14}{6}+0\times 2\right)\times 9-\frac{11}{4}}$$

Whakahekea te hautanga \frac{14}{6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$\sqrt{\left(\frac{7}{3}+0\times 2\right)\times 9-\frac{11}{4}}$$

Whakareatia te 0 ki te 2, ka 0.

$$\sqrt{\left(\frac{7}{3}+0\right)\times 9-\frac{11}{4}}$$

Tāpirihia te \frac{7}{3} ki te 0, ka \frac{7}{3}.

$$\sqrt{\frac{7}{3}\times 9-\frac{11}{4}}$$

Tuhia te \frac{7}{3}\times 9 hei hautanga kotahi.

$$\sqrt{\frac{7\times 9}{3}-\frac{11}{4}}$$

Whakareatia te 7 ki te 9, ka 63.

$$\sqrt{\frac{63}{3}-\frac{11}{4}}$$

Whakawehea te 63 ki te 3, kia riro ko 21.

$$\sqrt{21-\frac{11}{4}}$$

Me tahuri te 21 ki te hautau \frac{84}{4}.

$$\sqrt{\frac{84}{4}-\frac{11}{4}}$$

Tā te mea he rite te tauraro o \frac{84}{4} me \frac{11}{4}, me tango rāua mā te tango i ō raua taurunga.

$$\sqrt{\frac{84-11}{4}}$$

Tangohia te 11 i te 84, ka 73.

$$\sqrt{\frac{73}{4}}$$

Tuhia anō te pūtake rua o te whakawehenga \sqrt{\frac{73}{4}} hei whakawehenga o ngā pūtake rua \frac{\sqrt{73}}{\sqrt{4}}.

$$\frac{\sqrt{73}}{\sqrt{4}}$$

Tātaitia te pūtakerua o 4 kia tae ki 2.

$$\frac{\sqrt{73}}{2}$$