Whakaoti i te sin^2pi/4+1

$$\sin ^ { 2 } \frac { \pi } { 4 } + 1$$

Aromātai

$$\frac{3}{2}=1.5$$

Ngā Upane Otinga

Tīkina te uara \sin(\frac{\pi }{4}) mai i te ripanga uara pākoki.

$$\left(\frac{\sqrt{2}}{2}\right)^{2}+1$$

Kia whakarewa i te \frac{\sqrt{2}}{2} ki tētahi taupū, me whakarewa tahi te taurunga me te tauraro ki te taupū kātahi ka whakawehe.

$$\frac{\left(\sqrt{2}\right)^{2}}{2^{2}}+1$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 1 ki te \frac{2^{2}}{2^{2}}.

$$\frac{\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{2^{2}}{2^{2}}$$

Tā te mea he rite te tauraro o \frac{\left(\sqrt{2}\right)^{2}}{2^{2}} me \frac{2^{2}}{2^{2}}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{\left(\sqrt{2}\right)^{2}+2^{2}}{2^{2}}$$

Ko te pūrua o \sqrt{2} ko 2.

$$\frac{2}{2^{2}}+1$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$\frac{2}{4}+1$$

Whakahekea te hautanga \frac{2}{4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$\frac{1}{2}+1$$

Tāpirihia te \frac{1}{2} ki te 1, ka \frac{3}{2}.

$$\frac{3}{2}$$

Tauwehe

$$\frac{3}{2} = 1\frac{1}{2} = 1.5$$