Whakaoti i te sigma_x^2=(-2-0)^2*4/9+(0*0)^2x

$$\sigma _ { x } ^ { 2 } = ( - 2 - 0 ) ^ { 2 } \times \frac { 4 } { 9 } + ( 0 \times 0 ) ^ { 2 } x$$

Whakaoti mō σ_x

$$\sigma _{x}=\frac{4}{3}$$

$$\sigma _{x}=-\frac{4}{3}$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 0 i te -2, ka -2.

$$\sigma _{x}^{2}=\left(-2\right)^{2}\times \frac{4}{9}+\left(0\times 0\right)^{2}x$$

Tātaihia te -2 mā te pū o 2, kia riro ko 4.

$$\sigma _{x}^{2}=4\times \frac{4}{9}+\left(0\times 0\right)^{2}x$$

Whakareatia te 4 ki te \frac{4}{9}, ka \frac{16}{9}.

$$\sigma _{x}^{2}=\frac{16}{9}+\left(0\times 0\right)^{2}x$$

Whakareatia te 0 ki te 0, ka 0.

$$\sigma _{x}^{2}=\frac{16}{9}+0^{2}x$$

Tātaihia te 0 mā te pū o 2, kia riro ko 0.

$$\sigma _{x}^{2}=\frac{16}{9}+0x$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$\sigma _{x}^{2}=\frac{16}{9}+0$$

Tāpirihia te \frac{16}{9} ki te 0, ka \frac{16}{9}.

$$\sigma _{x}^{2}=\frac{16}{9}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sigma _{x}=\frac{4}{3} \sigma _{x}=-\frac{4}{3}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 0 i te -2, ka -2.

$$\sigma _{x}^{2}=\left(-2\right)^{2}\times \frac{4}{9}+\left(0\times 0\right)^{2}x$$

Tātaihia te -2 mā te pū o 2, kia riro ko 4.

$$\sigma _{x}^{2}=4\times \frac{4}{9}+\left(0\times 0\right)^{2}x$$

Whakareatia te 4 ki te \frac{4}{9}, ka \frac{16}{9}.

$$\sigma _{x}^{2}=\frac{16}{9}+\left(0\times 0\right)^{2}x$$

Whakareatia te 0 ki te 0, ka 0.

$$\sigma _{x}^{2}=\frac{16}{9}+0^{2}x$$

Tātaihia te 0 mā te pū o 2, kia riro ko 0.

$$\sigma _{x}^{2}=\frac{16}{9}+0x$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$\sigma _{x}^{2}=\frac{16}{9}+0$$

Tāpirihia te \frac{16}{9} ki te 0, ka \frac{16}{9}.

$$\sigma _{x}^{2}=\frac{16}{9}$$

Tangohia te \frac{16}{9} mai i ngā taha e rua.

$$\sigma _{x}^{2}-\frac{16}{9}=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -\frac{16}{9} mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$\sigma _{x}=\frac{0±\sqrt{0^{2}-4\left(-\frac{16}{9}\right)}}{2}$$

Pūrua 0.

$$\sigma _{x}=\frac{0±\sqrt{-4\left(-\frac{16}{9}\right)}}{2}$$

Whakareatia -4 ki te -\frac{16}{9}.

$$\sigma _{x}=\frac{0±\sqrt{\frac{64}{9}}}{2}$$

Tuhia te pūtakerua o te \frac{64}{9}.

$$\sigma _{x}=\frac{0±\frac{8}{3}}{2}$$

Nā, me whakaoti te whārite \sigma _{x}=\frac{0±\frac{8}{3}}{2} ina he tāpiri te ±.

$$\sigma _{x}=\frac{4}{3}$$

Nā, me whakaoti te whārite \sigma _{x}=\frac{0±\frac{8}{3}}{2} ina he tango te ±.

$$\sigma _{x}=-\frac{4}{3}$$

Kua oti te whārite te whakatau.

$$\sigma _{x}=\frac{4}{3} \sigma _{x}=-\frac{4}{3}$$

Whakaoti mō x (complex solution)

$$x\in \mathrm{C}$$

$$\sigma _{x}=\frac{4}{3}\text{ or }\sigma _{x}=-\frac{4}{3}$$

Whakaoti mō x

$$x\in \mathrm{R}$$

$$|\sigma _{x}|=\frac{4}{3}$$