Whakaoti i te secQ

$$\sec Q$$

Kimi Pārōnaki e ai ki Q

$$\frac{\tan(Q)}{\cos(Q)}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Whakamahia te tautuhinga o te whenu taupoki.

$$\frac{\mathrm{d}}{\mathrm{d}Q}(\frac{1}{\cos(Q)})$$

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\cos(Q)\frac{\mathrm{d}}{\mathrm{d}Q}(1)-\frac{\mathrm{d}}{\mathrm{d}Q}(\cos(Q))}{\left(\cos(Q)\right)^{2}}$$

Ko te pārōnaki o te pūmau 1 ko 0, ā, ko te pārōnaki o cos(Q) ko −sin(Q).

$$-\frac{-\sin(Q)}{\left(\cos(Q)\right)^{2}}$$

Whakarūnātia.

$$\frac{\sin(Q)}{\left(\cos(Q)\right)^{2}}$$

Tuhia anō te otinga hei hua o ngā otinga e rua.

$$\frac{1}{\cos(Q)}\times \frac{\sin(Q)}{\cos(Q)}$$

Whakamahia te tautuhinga o te whenu taupoki.

$$\sec(Q)\times \frac{\sin(Q)}{\cos(Q)}$$

Whakamahia te tautuhinga o te pātapa.

$$\sec(Q)\tan(Q)$$

Aromātai

$$\frac{1}{\cos(Q)}$$