Whakaoti i te pir^2=48

$$\pi r ^ { 2 } = 48$$

Whakaoti mō r

$$r=4\sqrt{\frac{3}{\pi }}\approx 3.908820095$$

$$r=-4\sqrt{\frac{3}{\pi }}\approx -3.908820095$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te \pi .

$$\frac{\pi r^{2}}{\pi }=\frac{48}{\pi }$$

Mā te whakawehe ki te \pi ka wetekia te whakareanga ki te \pi .

$$r^{2}=\frac{48}{\pi }$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$r=\frac{12}{\sqrt{3\pi }} r=-\frac{12}{\sqrt{3\pi }}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 48 mai i ngā taha e rua.

$$\pi r^{2}-48=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi \pi mō a, 0 mō b, me -48 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$r=\frac{0±\sqrt{0^{2}-4\pi \left(-48\right)}}{2\pi }$$

Pūrua 0.

$$r=\frac{0±\sqrt{-4\pi \left(-48\right)}}{2\pi }$$

Whakareatia -4 ki te \pi .

$$r=\frac{0±\sqrt{\left(-4\pi \right)\left(-48\right)}}{2\pi }$$

Whakareatia -4\pi ki te -48.

$$r=\frac{0±\sqrt{192\pi }}{2\pi }$$

Tuhia te pūtakerua o te 192\pi .

$$r=\frac{0±8\sqrt{3\pi }}{2\pi }$$

Nā, me whakaoti te whārite r=\frac{0±8\sqrt{3\pi }}{2\pi } ina he tāpiri te ±.

$$r=\frac{12}{\sqrt{3\pi }}$$

Nā, me whakaoti te whārite r=\frac{0±8\sqrt{3\pi }}{2\pi } ina he tango te ±.

$$r=-\frac{12}{\sqrt{3\pi }}$$

Kua oti te whārite te whakatau.

$$r=\frac{12}{\sqrt{3\pi }} r=-\frac{12}{\sqrt{3\pi }}$$