Whakaoti i te pigamma^2=4pi

$$\pi \gamma ^ { 2 } = 4 \pi$$

Whakaoti mō γ

$$\gamma =2$$

$$\gamma =-2$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Me whakakore te \pi ki ngā taha e rua.

$$\gamma ^{2}=4$$

Tangohia te 4 mai i ngā taha e rua.

$$\gamma ^{2}-4=0$$

Whakaarohia te \gamma ^{2}-4. Tuhia anō te \gamma ^{2}-4 hei \gamma ^{2}-2^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(\gamma -2\right)\left(\gamma +2\right)=0$$

Hei kimi otinga whārite, me whakaoti te \gamma -2=0 me te \gamma +2=0.

$$\gamma =2 \gamma =-2$$

Ngā Upane mā te Kimi Pūtakerua

Me whakakore te \pi ki ngā taha e rua.

$$\gamma ^{2}=4$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\gamma =2 \gamma =-2$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Me whakakore te \pi ki ngā taha e rua.

$$\gamma ^{2}=4$$

Tangohia te 4 mai i ngā taha e rua.

$$\gamma ^{2}-4=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -4 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$\gamma =\frac{0±\sqrt{0^{2}-4\left(-4\right)}}{2}$$

Pūrua 0.

$$\gamma =\frac{0±\sqrt{-4\left(-4\right)}}{2}$$

Whakareatia -4 ki te -4.

$$\gamma =\frac{0±\sqrt{16}}{2}$$

Tuhia te pūtakerua o te 16.

$$\gamma =\frac{0±4}{2}$$

Nā, me whakaoti te whārite \gamma =\frac{0±4}{2} ina he tāpiri te ±. Whakawehe 4 ki te 2.

$$\gamma =2$$

Nā, me whakaoti te whārite \gamma =\frac{0±4}{2} ina he tango te ±. Whakawehe -4 ki te 2.

$$\gamma =-2$$

Kua oti te whārite te whakatau.

$$\gamma =2 \gamma =-2$$