Whakaoti i te pi*r^2=3

$$\pi \cdot r ^ { 2 } = 3$$

Whakaoti mō r

$$r=\sqrt{\frac{3}{\pi }}\approx 0.977205024$$

$$r=-\sqrt{\frac{3}{\pi }}\approx -0.977205024$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te \pi .

$$\frac{\pi r^{2}}{\pi }=\frac{3}{\pi }$$

Mā te whakawehe ki te \pi ka wetekia te whakareanga ki te \pi .

$$r^{2}=\frac{3}{\pi }$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$r=\frac{3}{\sqrt{3\pi }} r=-\frac{3}{\sqrt{3\pi }}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 3 mai i ngā taha e rua.

$$\pi r^{2}-3=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi \pi mō a, 0 mō b, me -3 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$r=\frac{0±\sqrt{0^{2}-4\pi \left(-3\right)}}{2\pi }$$

Pūrua 0.

$$r=\frac{0±\sqrt{-4\pi \left(-3\right)}}{2\pi }$$

Whakareatia -4 ki te \pi .

$$r=\frac{0±\sqrt{\left(-4\pi \right)\left(-3\right)}}{2\pi }$$

Whakareatia -4\pi ki te -3.

$$r=\frac{0±\sqrt{12\pi }}{2\pi }$$

Tuhia te pūtakerua o te 12\pi .

$$r=\frac{0±2\sqrt{3\pi }}{2\pi }$$

Nā, me whakaoti te whārite r=\frac{0±2\sqrt{3\pi }}{2\pi } ina he tāpiri te ±.

$$r=\frac{3}{\sqrt{3\pi }}$$

Nā, me whakaoti te whārite r=\frac{0±2\sqrt{3\pi }}{2\pi } ina he tango te ±.

$$r=-\frac{3}{\sqrt{3\pi }}$$

Kua oti te whārite te whakatau.

$$r=\frac{3}{\sqrt{3\pi }} r=-\frac{3}{\sqrt{3\pi }}$$