Whakaoti i te pir^2=100-x

$$\pi { r }^{ 2 } =100-x$$

Whakaoti mō x

$$x=100-\pi r^{2}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$100-x=\pi r^{2}$$

Tangohia te 100 mai i ngā taha e rua.

$$-x=\pi r^{2}-100$$

Whakawehea ngā taha e rua ki te -1.

$$\frac{-x}{-1}=\frac{\pi r^{2}-100}{-1}$$

Mā te whakawehe ki te -1 ka wetekia te whakareanga ki te -1.

$$x=\frac{\pi r^{2}-100}{-1}$$

Whakawehe \pi r^{2}-100 ki te -1.

$$x=100-\pi r^{2}$$

Whakaoti mō r (complex solution)

$$r=-i\sqrt{\frac{x-100}{\pi }}$$

$$r=i\sqrt{\frac{x-100}{\pi }}$$

Whakaoti mō r

$$r=\sqrt{\frac{100-x}{\pi }}$$

$$r=-\sqrt{\frac{100-x}{\pi }}\text{, }x\leq 100$$