Whakaoti i te phi(2sqrt{48}-3sqrt{27})divsqrt{6}

$$\phi ( 2 \sqrt { 48 } - 3 \sqrt { 27 } ) \div \sqrt { 6 }$$

Aromātai

$$-\frac{\sqrt{2}ϕ}{2}$$

Ngā Upane Otinga

Tauwehea te 48=4^{2}\times 3. Tuhia anō te pūtake rua o te hua \sqrt{4^{2}\times 3} hei hua o ngā pūtake rua \sqrt{4^{2}}\sqrt{3}. Tuhia te pūtakerua o te 4^{2}.

$$\frac{ϕ\left(2\times 4\sqrt{3}-3\sqrt{27}\right)}{\sqrt{6}}$$

Whakareatia te 2 ki te 4, ka 8.

$$\frac{ϕ\left(8\sqrt{3}-3\sqrt{27}\right)}{\sqrt{6}}$$

Tauwehea te 27=3^{2}\times 3. Tuhia anō te pūtake rua o te hua \sqrt{3^{2}\times 3} hei hua o ngā pūtake rua \sqrt{3^{2}}\sqrt{3}. Tuhia te pūtakerua o te 3^{2}.

$$\frac{ϕ\left(8\sqrt{3}-3\times 3\sqrt{3}\right)}{\sqrt{6}}$$

Whakareatia te -3 ki te 3, ka -9.

$$\frac{ϕ\left(8\sqrt{3}-9\sqrt{3}\right)}{\sqrt{6}}$$

Pahekotia te 8\sqrt{3} me -9\sqrt{3}, ka -\sqrt{3}.

$$\frac{ϕ\left(-1\right)\sqrt{3}}{\sqrt{6}}$$

Whakangāwaritia te tauraro o \frac{ϕ\left(-1\right)\sqrt{3}}{\sqrt{6}} mā te whakarea i te taurunga me te tauraro ki te \sqrt{6}.

$$\frac{ϕ\left(-1\right)\sqrt{3}\sqrt{6}}{\left(\sqrt{6}\right)^{2}}$$

Ko te pūrua o \sqrt{6} ko 6.

$$\frac{ϕ\left(-1\right)\sqrt{3}\sqrt{6}}{6}$$

Tauwehea te 6=3\times 2. Tuhia anō te pūtake rua o te hua \sqrt{3\times 2} hei hua o ngā pūtake rua \sqrt{3}\sqrt{2}.

$$\frac{ϕ\left(-1\right)\sqrt{3}\sqrt{3}\sqrt{2}}{6}$$

Whakareatia te \sqrt{3} ki te \sqrt{3}, ka 3.

$$\frac{ϕ\left(-1\right)\times 3\sqrt{2}}{6}$$

Whakareatia te -1 ki te 3, ka -3.

$$\frac{ϕ\left(-3\right)\sqrt{2}}{6}$$

Whakawehea te ϕ\left(-3\right)\sqrt{2} ki te 6, kia riro ko ϕ\left(-\frac{1}{2}\right)\sqrt{2}.

$$ϕ\left(-\frac{1}{2}\right)\sqrt{2}$$

Kimi Pārōnaki e ai ki ϕ

$$-\frac{\sqrt{2}}{2} = -0.7071067811865476$$