Whakaoti i te phi=(4500N*C^{-1})(123.36*10^{-4}m^2)cos{tan^-1(18.5*10^-2m)/(frac{122{2}*10^-2m)}}

$$\phi = ( 4500 N \cdot C ^ { - 1 } ) ( 123.36 \times 10 ^ { - 4 } m ^ { 2 } ) \cos \{ \tan ^ { - 1 } \frac { ( 18.5 \times 10 ^ { - 2 } m ) } { ( \frac { 122 } { 2 } \times 10 ^ { - 2 } m ) } \}$$

Whakaoti mō N

$$N=\frac{125\sqrt{16253}Cϕ}{846558m^{2}}$$

$$C\neq 0\text{ and }m\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te 4500 ki te 123.36, ka 555120.

$$ϕ=555120NC^{-1}\times 10^{-4}m^{2}\cos(\arctan(\frac{18.5\times 10^{-2}m}{\frac{122}{2}\times 10^{-2}m}))$$

Tātaihia te 10 mā te pū o -4, kia riro ko \frac{1}{10000}.

$$ϕ=555120NC^{-1}\times \frac{1}{10000}m^{2}\cos(\arctan(\frac{18.5\times 10^{-2}m}{\frac{122}{2}\times 10^{-2}m}))$$

Whakareatia te 555120 ki te \frac{1}{10000}, ka \frac{6939}{125}.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{18.5\times 10^{-2}m}{\frac{122}{2}\times 10^{-2}m}))$$

Tātaihia te 10 mā te pū o -2, kia riro ko \frac{1}{100}.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{18.5\times \frac{1}{100}m}{\frac{122}{2}\times 10^{-2}m}))$$

Whakareatia te 18.5 ki te \frac{1}{100}, ka \frac{37}{200}.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{\frac{37}{200}m}{\frac{122}{2}\times 10^{-2}m}))$$

Whakawehea te 122 ki te 2, kia riro ko 61.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{\frac{37}{200}m}{61\times 10^{-2}m}))$$

Tātaihia te 10 mā te pū o -2, kia riro ko \frac{1}{100}.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{\frac{37}{200}m}{61\times \frac{1}{100}m}))$$

Whakareatia te 61 ki te \frac{1}{100}, ka \frac{61}{100}.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{\frac{37}{200}m}{\frac{61}{100}m}))$$

Me whakakore tahi te m i te taurunga me te tauraro.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{\frac{37}{200}}{\frac{61}{100}}))$$

Whakawehe \frac{37}{200} ki te \frac{61}{100} mā te whakarea \frac{37}{200} ki te tau huripoki o \frac{61}{100}.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{37}{200}\times \frac{100}{61}))$$

Whakareatia te \frac{37}{200} ki te \frac{100}{61}, ka \frac{37}{122}.

$$ϕ=\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{37}{122}))$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\frac{6939}{125}NC^{-1}m^{2}\cos(\arctan(\frac{37}{122}))=ϕ$$

He hanga arowhānui tō te whārite.

$$\frac{6939\cos(\arctan(\frac{37}{122}))m^{2}}{125C}N=ϕ$$

Whakawehea ngā taha e rua ki te \frac{6939}{125}C^{-1}m^{2}\cos(\arctan(\frac{37}{122})).

$$\frac{\frac{6939\cos(\arctan(\frac{37}{122}))m^{2}}{125C}N\times 125C}{6939\cos(\arctan(\frac{37}{122}))m^{2}}=\frac{ϕ\times 125C}{6939\cos(\arctan(\frac{37}{122}))m^{2}}$$

Mā te whakawehe ki te \frac{6939}{125}C^{-1}m^{2}\cos(\arctan(\frac{37}{122})) ka wetekia te whakareanga ki te \frac{6939}{125}C^{-1}m^{2}\cos(\arctan(\frac{37}{122})).

$$N=\frac{ϕ\times 125C}{6939\cos(\arctan(\frac{37}{122}))m^{2}}$$

Whakawehe ϕ ki te \frac{6939}{125}C^{-1}m^{2}\cos(\arctan(\frac{37}{122})).

$$N=\frac{125\sqrt{16253}Cϕ}{846558m^{2}}$$

Whakaoti mō C

$$\left\{\begin{matrix}\\C\neq 0\text{, }&\text{unconditionally}\\C=\frac{846558\sqrt{16253}Nm^{2}}{2031625ϕ}\text{, }&m\neq 0\text{ and }N\neq 0\text{ and }ϕ\neq 0\end{matrix}\right.$$