Whakaoti i te operatorname{ph}5x+3y=15

$$\operatorname { ph } 5 x + 3 y = 15$$

Whakaoti mō h_5 (complex solution)

$$\left\{\begin{matrix}h_{5}=-\frac{3\left(y-5\right)}{px}\text{, }&x\neq 0\text{ and }p\neq 0\\h_{5}\in \mathrm{C}\text{, }&\left(x=0\text{ or }p=0\right)\text{ and }y=5\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 3y mai i ngā taha e rua.

$$ph_{5}x=15-3y$$

He hanga arowhānui tō te whārite.

$$pxh_{5}=15-3y$$

Whakawehea ngā taha e rua ki te px.

$$\frac{pxh_{5}}{px}=\frac{15-3y}{px}$$

Mā te whakawehe ki te px ka wetekia te whakareanga ki te px.

$$h_{5}=\frac{15-3y}{px}$$

Whakawehe 15-3y ki te px.

$$h_{5}=\frac{3\left(5-y\right)}{px}$$

Whakaoti mō p (complex solution)

$$\left\{\begin{matrix}p=-\frac{3\left(y-5\right)}{h_{5}x}\text{, }&x\neq 0\text{ and }h_{5}\neq 0\\p\in \mathrm{C}\text{, }&\left(x=0\text{ or }h_{5}=0\right)\text{ and }y=5\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 3y mai i ngā taha e rua.

$$ph_{5}x=15-3y$$

He hanga arowhānui tō te whārite.

$$h_{5}xp=15-3y$$

Whakawehea ngā taha e rua ki te h_{5}x.

$$\frac{h_{5}xp}{h_{5}x}=\frac{15-3y}{h_{5}x}$$

Mā te whakawehe ki te h_{5}x ka wetekia te whakareanga ki te h_{5}x.

$$p=\frac{15-3y}{h_{5}x}$$

Whakawehe 15-3y ki te h_{5}x.

$$p=\frac{3\left(5-y\right)}{h_{5}x}$$

Whakaoti mō h_5

$$\left\{\begin{matrix}h_{5}=-\frac{3\left(y-5\right)}{px}\text{, }&x\neq 0\text{ and }p\neq 0\\h_{5}\in \mathrm{R}\text{, }&\left(x=0\text{ or }p=0\right)\text{ and }y=5\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 3y mai i ngā taha e rua.

$$ph_{5}x=15-3y$$

He hanga arowhānui tō te whārite.

$$pxh_{5}=15-3y$$

Whakawehea ngā taha e rua ki te px.

$$\frac{pxh_{5}}{px}=\frac{15-3y}{px}$$

Mā te whakawehe ki te px ka wetekia te whakareanga ki te px.

$$h_{5}=\frac{15-3y}{px}$$

Whakawehe 15-3y ki te px.

$$h_{5}=\frac{3\left(5-y\right)}{px}$$

Whakaoti mō p

$$\left\{\begin{matrix}p=-\frac{3\left(y-5\right)}{h_{5}x}\text{, }&x\neq 0\text{ and }h_{5}\neq 0\\p\in \mathrm{R}\text{, }&\left(x=0\text{ or }h_{5}=0\right)\text{ and }y=5\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 3y mai i ngā taha e rua.

$$ph_{5}x=15-3y$$

He hanga arowhānui tō te whārite.

$$h_{5}xp=15-3y$$

Whakawehea ngā taha e rua ki te h_{5}x.

$$\frac{h_{5}xp}{h_{5}x}=\frac{15-3y}{h_{5}x}$$

Mā te whakawehe ki te h_{5}x ka wetekia te whakareanga ki te h_{5}x.

$$p=\frac{15-3y}{h_{5}x}$$

Whakawehe 15-3y ki te h_{5}x.

$$p=\frac{3\left(5-y\right)}{h_{5}x}$$