Whakaoti i te operatorname{lom}(x-pi/2)=cosx

$$\operatorname { lom } ( x - \frac { \pi } { 2 } ) = \cos x$$

Whakaoti mō l (complex solution)

$$\left\{\begin{matrix}l=\frac{2\cos(x)}{mo\left(2x-\pi \right)}\text{, }&x\neq \frac{\pi }{2}\text{ and }m\neq 0\text{ and }o\neq 0\\l\in \mathrm{C}\text{, }&\exists n_{1}\in \mathrm{Z}\text{ : }x=\pi n_{1}+\frac{\pi }{2}\text{ or }x=\frac{\pi }{2}\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 2.

$$2lom\left(x-\frac{\pi }{2}\right)=2\cos(x)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2lom ki te x-\frac{\pi }{2}.

$$2lomx+2lom\left(-\frac{\pi }{2}\right)=2\cos(x)$$

Tuhia te 2\left(-\frac{\pi }{2}\right) hei hautanga kotahi.

$$2lomx+\frac{-2\pi }{2}lom=2\cos(x)$$

Me whakakore te 2 me te 2.

$$2lomx-\pi lom=2\cos(x)$$

Pahekotia ngā kīanga tau katoa e whai ana i te l.

$$\left(2omx-\pi om\right)l=2\cos(x)$$

He hanga arowhānui tō te whārite.

$$\left(2mox-\pi mo\right)l=2\cos(x)$$

Whakawehea ngā taha e rua ki te 2mox-mo\pi .

$$\frac{\left(2mox-\pi mo\right)l}{2mox-\pi mo}=\frac{2\cos(x)}{2mox-\pi mo}$$

Mā te whakawehe ki te 2mox-mo\pi ka wetekia te whakareanga ki te 2mox-mo\pi .

$$l=\frac{2\cos(x)}{2mox-\pi mo}$$

Whakawehe 2\cos(x) ki te 2mox-mo\pi .

$$l=\frac{2\cos(x)}{mo\left(2x-\pi \right)}$$

Whakaoti mō m (complex solution)

$$\left\{\begin{matrix}m=\frac{2\cos(x)}{lo\left(2x-\pi \right)}\text{, }&x\neq \frac{\pi }{2}\text{ and }o\neq 0\text{ and }l\neq 0\\m\in \mathrm{C}\text{, }&\exists n_{1}\in \mathrm{Z}\text{ : }x=\pi n_{1}+\frac{\pi }{2}\text{ or }x=\frac{\pi }{2}\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 2.

$$2lom\left(x-\frac{\pi }{2}\right)=2\cos(x)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2lom ki te x-\frac{\pi }{2}.

$$2lomx+2lom\left(-\frac{\pi }{2}\right)=2\cos(x)$$

Tuhia te 2\left(-\frac{\pi }{2}\right) hei hautanga kotahi.

$$2lomx+\frac{-2\pi }{2}lom=2\cos(x)$$

Me whakakore te 2 me te 2.

$$2lomx-\pi lom=2\cos(x)$$

Pahekotia ngā kīanga tau katoa e whai ana i te m.

$$\left(2lox-\pi lo\right)m=2\cos(x)$$

Whakawehea ngā taha e rua ki te 2olx-ol\pi .

$$\frac{\left(2lox-\pi lo\right)m}{2lox-\pi lo}=\frac{2\cos(x)}{2lox-\pi lo}$$

Mā te whakawehe ki te 2olx-ol\pi ka wetekia te whakareanga ki te 2olx-ol\pi .

$$m=\frac{2\cos(x)}{2lox-\pi lo}$$

Whakawehe 2\cos(x) ki te 2olx-ol\pi .

$$m=\frac{2\cos(x)}{lo\left(2x-\pi \right)}$$

Whakaoti mō l

$$\left\{\begin{matrix}l=\frac{2\cos(x)}{mo\left(2x-\pi \right)}\text{, }&x\neq \frac{\pi }{2}\text{ and }m\neq 0\text{ and }o\neq 0\\l\in \mathrm{R}\text{, }&\exists n_{1}\in \mathrm{Z}\text{ : }x=\pi n_{1}+\frac{\pi }{2}\text{ or }x=\frac{\pi }{2}\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 2.

$$2lom\left(x-\frac{\pi }{2}\right)=2\cos(x)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2lom ki te x-\frac{\pi }{2}.

$$2lomx+2lom\left(-\frac{\pi }{2}\right)=2\cos(x)$$

Tuhia te 2\left(-\frac{\pi }{2}\right) hei hautanga kotahi.

$$2lomx+\frac{-2\pi }{2}lom=2\cos(x)$$

Me whakakore te 2 me te 2.

$$2lomx-\pi lom=2\cos(x)$$

Pahekotia ngā kīanga tau katoa e whai ana i te l.

$$\left(2omx-\pi om\right)l=2\cos(x)$$

He hanga arowhānui tō te whārite.

$$\left(2mox-\pi mo\right)l=2\cos(x)$$

Whakawehea ngā taha e rua ki te 2omx-\pi om.

$$\frac{\left(2mox-\pi mo\right)l}{2mox-\pi mo}=\frac{2\cos(x)}{2mox-\pi mo}$$

Mā te whakawehe ki te 2omx-\pi om ka wetekia te whakareanga ki te 2omx-\pi om.

$$l=\frac{2\cos(x)}{2mox-\pi mo}$$

Whakawehe 2\cos(x) ki te 2omx-\pi om.

$$l=\frac{2\cos(x)}{mo\left(2x-\pi \right)}$$

Whakaoti mō m

$$\left\{\begin{matrix}m=\frac{2\cos(x)}{lo\left(2x-\pi \right)}\text{, }&x\neq \frac{\pi }{2}\text{ and }l\neq 0\text{ and }o\neq 0\\m\in \mathrm{R}\text{, }&\exists n_{1}\in \mathrm{Z}\text{ : }x=\pi n_{1}+\frac{\pi }{2}\text{ or }x=\frac{\pi }{2}\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 2.

$$2lom\left(x-\frac{\pi }{2}\right)=2\cos(x)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2lom ki te x-\frac{\pi }{2}.

$$2lomx+2lom\left(-\frac{\pi }{2}\right)=2\cos(x)$$

Tuhia te 2\left(-\frac{\pi }{2}\right) hei hautanga kotahi.

$$2lomx+\frac{-2\pi }{2}lom=2\cos(x)$$

Me whakakore te 2 me te 2.

$$2lomx-\pi lom=2\cos(x)$$

Pahekotia ngā kīanga tau katoa e whai ana i te m.

$$\left(2lox-\pi lo\right)m=2\cos(x)$$

Whakawehea ngā taha e rua ki te 2lox-\pi lo.

$$\frac{\left(2lox-\pi lo\right)m}{2lox-\pi lo}=\frac{2\cos(x)}{2lox-\pi lo}$$

Mā te whakawehe ki te 2lox-\pi lo ka wetekia te whakareanga ki te 2lox-\pi lo.

$$m=\frac{2\cos(x)}{2lox-\pi lo}$$

Whakawehe 2\cos(x) ki te 2lox-\pi lo.

$$m=\frac{2\cos(x)}{lo\left(2x-\pi \right)}$$