Whakaoti i te operatorname{h}(x)=x^2+6^x-27/x^2-8x+7

$$\operatorname { h } ( x ) = \frac { x ^ { 2 } + 6 ^ { x } - 27 } { x ^ { 2 } - 8 x + 7 }$$

Whakaoti mō h

$$h=-\frac{27-6^{x}-x^{2}}{x\left(x-7\right)\left(x-1\right)}$$

$$x\neq 1\text{ and }x\neq 7\text{ and }x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te \left(x-7\right)\left(x-1\right).

$$hx\left(x-7\right)\left(x-1\right)=x^{2}+6^{x}-27$$

Whakamahia te āhuatanga tohatoha hei whakarea te hx ki te x-7.

$$\left(hx^{2}-7hx\right)\left(x-1\right)=x^{2}+6^{x}-27$$

Whakamahia te āhuatanga tuaritanga hei whakarea te hx^{2}-7hx ki te x-1 ka whakakotahi i ngā kupu rite.

$$hx^{3}-8hx^{2}+7hx=x^{2}+6^{x}-27$$

Pahekotia ngā kīanga tau katoa e whai ana i te h.

$$\left(x^{3}-8x^{2}+7x\right)h=x^{2}+6^{x}-27$$

Whakawehea ngā taha e rua ki te -8x^{2}+x^{3}+7x.

$$\frac{\left(x^{3}-8x^{2}+7x\right)h}{x^{3}-8x^{2}+7x}=\frac{x^{2}+6^{x}-27}{x^{3}-8x^{2}+7x}$$

Mā te whakawehe ki te -8x^{2}+x^{3}+7x ka wetekia te whakareanga ki te -8x^{2}+x^{3}+7x.

$$h=\frac{x^{2}+6^{x}-27}{x^{3}-8x^{2}+7x}$$

Whakawehe x^{2}+6^{x}-27 ki te -8x^{2}+x^{3}+7x.

$$h=\frac{x^{2}+6^{x}-27}{x\left(x-7\right)\left(x-1\right)}$$