Whakaoti i te log_{10}(10^-5/10)+log_{10}(10)-log_{10}(10^2)=

$$\log _ { 10 } ( \frac { 10 ^ { - 5 } } { 10 } ) + \log _ { 10 } ( 10 ) - \log _ { 10 } ( 10 ^ { 2 } ) =$$

Aromātai

$$-7$$

Ngā Upane Otinga

Tuhia anō te 10 hei 10^{-5}\times 10^{6}. Me whakakore tahi te 10^{-5} i te taurunga me te tauraro.

$$\log_{10}\left(\frac{1}{10^{6}}\right)+\log_{10}\left(10\right)-\log_{10}\left(10^{2}\right)$$

Tātaihia te 10 mā te pū o 6, kia riro ko 1000000.

$$\log_{10}\left(\frac{1}{1000000}\right)+\log_{10}\left(10\right)-\log_{10}\left(10^{2}\right)$$

Ko te taupū kōaro 10 pūtake o \frac{1}{1000000} ko -6.

$$-6+\log_{10}\left(10\right)-\log_{10}\left(10^{2}\right)$$

Ko te taupū kōaro 10 pūtake o 10 ko 1.

$$-6+1-\log_{10}\left(10^{2}\right)$$

Tāpirihia te -6 ki te 1, ka -5.

$$-5-\log_{10}\left(10^{2}\right)$$

Tātaihia te 10 mā te pū o 2, kia riro ko 100.

$$-5-\log_{10}\left(100\right)$$

Ko te taupū kōaro 10 pūtake o 100 ko 2.

$$-5-2$$

Tangohia te 2 i te -5, ka -7.

$$-7$$

Tauwehe

$$-7$$