Whakaoti i te {l}{2=c}{18=16a+4b+c}{8=-a-b+c}

$$\left. \begin{array}{l}{ 2 = c }\\{ 18 = 16 a + 4 b + c }\\{ 8 = - a - b + c }\end{array} \right.$$

Whakaoti mō c, a, b

$$c=2$$

$$a = \frac{10}{3} = 3\frac{1}{3} \approx 3.333333333$$

$$b = -\frac{28}{3} = -9\frac{1}{3} \approx -9.333333333$$

Ngā Hipanga Poto E Whakamahi Whakakapinga Ana

Me whakaoti te 2=c mō c.

$$c=2$$

Whakakapia te 2 mō te c i te whārite tuarua me te tuatoru.

$$18=16a+4b+2 8=-a-b+2$$

Me whakaoti ēnei whārite mō a me b takitahi.

$$a=1-\frac{1}{4}b b=-a-6$$

Whakakapia te 1-\frac{1}{4}b mō te a i te whārite b=-a-6.

$$b=-\left(1-\frac{1}{4}b\right)-6$$

Me whakaoti te b=-\left(1-\frac{1}{4}b\right)-6 mō b.

$$b=-\frac{28}{3}$$

Whakakapia te -\frac{28}{3} mō te b i te whārite a=1-\frac{1}{4}b.

$$a=1-\frac{1}{4}\left(-\frac{28}{3}\right)$$

Tātaitia te a i te a=1-\frac{1}{4}\left(-\frac{28}{3}\right).

$$a=\frac{10}{3}$$

Kua oti te pūnaha te whakatau.

$$c=2 a=\frac{10}{3} b=-\frac{28}{3}$$