Whakaoti i te {l}{y=x}{y=-x+sqrt{3}+1}

$$\left. \begin{array} { l } { y = x } \\ { y = - x + \sqrt { 3 } + 1 } \end{array} \right.$$

Whakaoti mō y, x

$$x = \frac{\sqrt{3} + 1}{2} \approx 1.366025404$$

$$y = \frac{\sqrt{3} + 1}{2} \approx 1.366025404$$

Ngā Upane e Whakamahi ana i te Whakakapinga

Whakaarohia te whārite tuatahi. Tangohia te x mai i ngā taha e rua.

$$y-x=0$$

Whakaarohia te whārite tuarua. Me tāpiri te x ki ngā taha e rua.

$$y+x=\sqrt{3}+1$$

Hei whakaoti i ētahi whārite takirua mā te whakakapinga, me whakaoti tētahi whārite i te tuatahi mō tētahi o ngā taurangi. Ka whakakapi i te otinga mō taua taurangi ki tērā o ngā whārite.

$$y-x=0,y+x=\sqrt{3}+1$$

Kōwhiria tētahi o ngā whārite ka whakaotia mō te y mā te wehe i te y i te taha mauī o te tohu ōrite.

$$y-x=0$$

Me tāpiri x ki ngā taha e rua o te whārite.

$$y=x$$

Whakakapia te x mō te y ki tērā atu whārite, y+x=\sqrt{3}+1.

$$x+x=\sqrt{3}+1$$

Tāpiri x ki te x.

$$2x=\sqrt{3}+1$$

Whakawehea ngā taha e rua ki te 2.

$$x=\frac{\sqrt{3}+1}{2}$$

Whakaurua te \frac{\sqrt{3}+1}{2} mō x ki y=x. I te mea kotahi anake te taurangi kei te whārite i puta, ka taea e koe te whakaoti mō y hāngai tonu.

$$y=\frac{\sqrt{3}+1}{2}$$

Kua oti te pūnaha te whakatau.

$$y=\frac{\sqrt{3}+1}{2},x=\frac{\sqrt{3}+1}{2}$$

Ngā Upane e Whakamahi i te Tangohanga

Whakaarohia te whārite tuatahi. Tangohia te x mai i ngā taha e rua.

$$y-x=0$$

Whakaarohia te whārite tuarua. Me tāpiri te x ki ngā taha e rua.

$$y+x=\sqrt{3}+1$$

Hei whakaoti mā te tangohanga, ko ngā tau whakarea o tētahi o ngā taurangi me mātua ōrite i ngā whārite e rua kia whakakorehia ai te taurangi ina tangohia tētahi whārite mai i tētahi atu.

$$y-x=0,y+x=\sqrt{3}+1$$

Me tango y+x=\sqrt{3}+1 mai i y-x=0 mā te tango i ngā kīanga tau ōrite i ia taha o te tohu ōrite.

$$y-y-x-x=-\left(\sqrt{3}+1\right)$$

Tāpiri y ki te -y. Ka whakakore atu ngā kupu y me -y, ka toe he whārite me tētahi taurangi kotahi ka taea te whakaoti.

$$-x-x=-\left(\sqrt{3}+1\right)$$

Tāpiri -x ki te -x.

$$-2x=-\left(\sqrt{3}+1\right)$$

Whakawehea ngā taha e rua ki te -2.

$$x=\frac{\sqrt{3}+1}{2}$$

Whakaurua te \frac{\sqrt{3}+1}{2} mō x ki y+x=\sqrt{3}+1. I te mea kotahi anake te taurangi kei te whārite i puta, ka taea e koe te whakaoti mō y hāngai tonu.

$$y+\frac{\sqrt{3}+1}{2}=\sqrt{3}+1$$

Me tango \frac{\sqrt{3}+1}{2} mai i ngā taha e rua o te whārite.

$$y=\frac{\sqrt{3}+1}{2}$$

Kua oti te pūnaha te whakatau.

$$y=\frac{\sqrt{3}+1}{2},x=\frac{\sqrt{3}+1}{2}$$