Whakaoti i te {l}{x_{1}-x_{2}=a}{(3/4x_{1}-1)=a}{(-x_{2}+b_{2}=a}

$$\left. \begin{array} { l } { x _ { 1 } - x _ { 2 } = a } \\ { ( \frac { 3 } { 4 } x _ { 1 } - 1 ) = a } \\ { ( - x _ { 2 } + b _ { 2 } = a } \end{array} \right.$$

Whakaoti mō x_1, x_2

$$x_{1}=\frac{4\left(a+1\right)}{3}$$

$$x_{2}=\frac{a+4}{3}$$

Ngā Upane e Whakamahi ana i te Whakakapinga

Hei whakaoti i ētahi whārite takirua mā te whakakapinga, me whakaoti tētahi whārite i te tuatahi mō tētahi o ngā taurangi. Ka whakakapi i te otinga mō taua taurangi ki tērā o ngā whārite.

$$\frac{3}{4}x_{1}-1=a,x_{1}-x_{2}=a$$

Tīpakohia tētahi o ngā whārite e rua he māmā ake ki te whakaoti mō te x_{1} mā te wehe i te x_{1} i te taha mauī o te tohu ōrite.

$$\frac{3}{4}x_{1}-1=a$$

Me tāpiri 1 ki ngā taha e rua o te whārite.

$$\frac{3}{4}x_{1}=a+1$$

Whakawehea ngā taha e rua o te whārite ki te \frac{3}{4}, he ōrite ki te whakarea i ngā taha e rua ki te tau huripoki o te hautanga.

$$x_{1}=\frac{4a+4}{3}$$

Whakakapia te \frac{4a+4}{3} mō te x_{1} ki tērā atu whārite, x_{1}-x_{2}=a.

$$\frac{4a+4}{3}-x_{2}=a$$

Me tango \frac{4+4a}{3} mai i ngā taha e rua o te whārite.

$$-x_{2}=\frac{-a-4}{3}$$

Whakawehea ngā taha e rua ki te -1.

$$x_{2}=\frac{a+4}{3}$$

Kua oti te pūnaha te whakatau.

$$x_{1}=\frac{4a+4}{3},x_{2}=\frac{a+4}{3}$$