Whakaoti i te {l}{f(x)=-x^2+3x+5}{x=-5/3}

$$\left. \begin{array} { l } { f ( x ) = - x ^ { 2 } + 3 x + 5 } \\ { x = - \frac { 5 } { 3 } } \end{array} \right.$$

Whakaoti mō f, x

$$x = -\frac{5}{3} = -1\frac{2}{3} \approx -1.666666667$$

$$f = \frac{5}{3} = 1\frac{2}{3} \approx 1.666666667$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$f\left(-\frac{5}{3}\right)=-\left(-\frac{5}{3}\right)^{2}+3\left(-\frac{5}{3}\right)+5$$

Tātaihia te -\frac{5}{3} mā te pū o 2, kia riro ko \frac{25}{9}.

$$f\left(-\frac{5}{3}\right)=-\frac{25}{9}+3\left(-\frac{5}{3}\right)+5$$

Whakareatia te 3 ki te -\frac{5}{3}, ka -5.

$$f\left(-\frac{5}{3}\right)=-\frac{25}{9}-5+5$$

Tangohia te 5 i te -\frac{25}{9}, ka -\frac{70}{9}.

$$f\left(-\frac{5}{3}\right)=-\frac{70}{9}+5$$

Tāpirihia te -\frac{70}{9} ki te 5, ka -\frac{25}{9}.

$$f\left(-\frac{5}{3}\right)=-\frac{25}{9}$$

Me whakarea ngā taha e rua ki te -\frac{3}{5}, te tau utu o -\frac{5}{3}.

$$f=-\frac{25}{9}\left(-\frac{3}{5}\right)$$

Whakareatia te -\frac{25}{9} ki te -\frac{3}{5}, ka \frac{5}{3}.

$$f=\frac{5}{3}$$

Kua oti te pūnaha te whakatau.

$$f=\frac{5}{3} x=-\frac{5}{3}$$