Whakaoti mō h, E, F (complex solution)
h = \frac{238}{5} = 47\frac{3}{5} = 47.6
E=-\frac{F}{2}+119000
F\in \mathrm{C}
Whakaoti mō h, E, F
h = \frac{238}{5} = 47\frac{3}{5} = 47.6
E=-\frac{F}{2}+119000
F\in \mathrm{R}
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