Whakaoti i te {l}{3y+x=z}{z=N+1}{y-x=5}

$$\left. \begin{array} { l } { 3 y + x = z } \\ { z = N + 1 } \\ { y - x = 5 } \end{array} \right.$$

Whakaoti mō x, y, z

$$x=\frac{N-14}{4}$$

$$y=\frac{N+6}{4}$$

$$z=N+1$$

Ngā Hipanga Poto E Whakamahi Whakakapinga Ana

Me whakaoti te 3y+x=z mō z.

$$z=3y+x$$

Whakakapia te 3y+x mō te z i te whārite z=N+1.

$$3y+x=N+1$$

Me whakaoti te whārite tuarua mō y me te whārite tuatoru mō x.

$$y=\frac{1}{3}-\frac{1}{3}x+\frac{1}{3}N x=y-5$$

Whakakapia te \frac{1}{3}-\frac{1}{3}x+\frac{1}{3}N mō te y i te whārite x=y-5.

$$x=\frac{1}{3}-\frac{1}{3}x+\frac{1}{3}N-5$$

Me whakaoti te x=\frac{1}{3}-\frac{1}{3}x+\frac{1}{3}N-5 mō x.

$$x=-\frac{7}{2}+\frac{1}{4}N$$

Whakakapia te -\frac{7}{2}+\frac{1}{4}N mō te x i te whārite y=\frac{1}{3}-\frac{1}{3}x+\frac{1}{3}N.

$$y=\frac{1}{3}-\frac{1}{3}\left(-\frac{7}{2}+\frac{1}{4}N\right)+\frac{1}{3}N$$

Tātaitia te y i te y=\frac{1}{3}-\frac{1}{3}\left(-\frac{7}{2}+\frac{1}{4}N\right)+\frac{1}{3}N.

$$y=\frac{3}{2}+\frac{1}{4}N$$

Whakakapia te \frac{3}{2}+\frac{1}{4}N mō te y me te -\frac{7}{2}+\frac{1}{4}N mō x i te whārite z=3y+x.

$$z=3\left(\frac{3}{2}+\frac{1}{4}N\right)-\frac{7}{2}+\frac{1}{4}N$$

Tātaitia te z i te z=3\left(\frac{3}{2}+\frac{1}{4}N\right)-\frac{7}{2}+\frac{1}{4}N.

$$z=1+N$$

Kua oti te pūnaha te whakatau.

$$x=-\frac{7}{2}+\frac{1}{4}N y=\frac{3}{2}+\frac{1}{4}N z=1+N$$