Whakaoti i te {l}{3=a+b+c}{-2=c}{-5=9a+3b+c}

$$\left. \begin{array} { l } { 3 = a + b + c } \\ { - 2 = c } \\ { - 5 = 9 a + 3 b + c } \end{array} \right.$$

Whakaoti mō a, b, c

$$a=-3$$

$$b=8$$

$$c=-2$$

Ngā Hipanga Poto E Whakamahi Whakakapinga Ana

Me raupapa anō ngā whārite.

$$-2=c 3=a+b+c -5=9a+3b+c$$

Me whakaoti te -2=c mō c.

$$c=-2$$

Whakakapia te -2 mō te c i te whārite tuarua me te tuatoru.

$$3=a+b-2 -5=9a+3b-2$$

Me whakaoti ēnei whārite mō b me a takitahi.

$$b=-a+5 a=-\frac{1}{3}-\frac{1}{3}b$$

Whakakapia te -a+5 mō te b i te whārite a=-\frac{1}{3}-\frac{1}{3}b.

$$a=-\frac{1}{3}-\frac{1}{3}\left(-a+5\right)$$

Me whakaoti te a=-\frac{1}{3}-\frac{1}{3}\left(-a+5\right) mō a.

$$a=-3$$

Whakakapia te -3 mō te a i te whārite b=-a+5.

$$b=-\left(-3\right)+5$$

Tātaitia te b i te b=-\left(-3\right)+5.

$$b=8$$

Kua oti te pūnaha te whakatau.

$$a=-3 b=8 c=-2$$