Whakaoti i te {l}{2x-3y=4}{3x+2y=6}

$$\left. \begin{array} { l } { 2 x - 3 y = 4 } \\ { 3 x + 2 y = 6 } \end{array} \right.$$

Whakaoti mō x, y

$$x=2$$

$$y=0$$

Ngā Upane e Whakamahi ana i te Whakakapinga

Hei whakaoti i ētahi whārite takirua mā te whakakapinga, me whakaoti tētahi whārite i te tuatahi mō tētahi o ngā taurangi. Ka whakakapi i te otinga mō taua taurangi ki tērā o ngā whārite.

$$2x-3y=4,3x+2y=6$$

Kōwhiria tētahi o ngā whārite ka whakaotia mō te x mā te wehe i te x i te taha mauī o te tohu ōrite.

$$2x-3y=4$$

Me tāpiri 3y ki ngā taha e rua o te whārite.

$$2x=3y+4$$

Whakawehea ngā taha e rua ki te 2.

$$x=\frac{1}{2}\left(3y+4\right)$$

Whakareatia \frac{1}{2} ki te 3y+4.

$$x=\frac{3}{2}y+2$$

Whakakapia te \frac{3y}{2}+2 mō te x ki tērā atu whārite, 3x+2y=6.

$$3\left(\frac{3}{2}y+2\right)+2y=6$$

Whakareatia 3 ki te \frac{3y}{2}+2.

$$\frac{9}{2}y+6+2y=6$$

Tāpiri \frac{9y}{2} ki te 2y.

$$\frac{13}{2}y+6=6$$

Me tango 6 mai i ngā taha e rua o te whārite.

$$\frac{13}{2}y=0$$

Whakawehea ngā taha e rua o te whārite ki te \frac{13}{2}, he ōrite ki te whakarea i ngā taha e rua ki te tau huripoki o te hautanga.

$$y=0$$

Whakaurua te 0 mō y ki x=\frac{3}{2}y+2. I te mea kotahi anake te taurangi kei te whārite i puta, ka taea e koe te whakaoti mō x hāngai tonu.

$$x=2$$

Kua oti te pūnaha te whakatau.

$$x=2,y=0$$

Ngā Upane e Whakamahi ana i Ngā Poukapa

Tuhia ngā whārite ki te tānga ngahuru ka whakamahi i ngā poukapa hei whakaoti i te pūnaha o ngā whārite.

$$2x-3y=4,3x+2y=6$$

Tuhia ngā whārite ki te tikanga tātai poukapa.

$$\left(\begin{matrix}2&-3\\3&2\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}4\\6\end{matrix}\right)$$

Whakarea mauī i te whārite ki te poukapa kōaro o \left(\begin{matrix}2&-3\\3&2\end{matrix}\right).

$$inverse(\left(\begin{matrix}2&-3\\3&2\end{matrix}\right))\left(\begin{matrix}2&-3\\3&2\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}2&-3\\3&2\end{matrix}\right))\left(\begin{matrix}4\\6\end{matrix}\right)$$

Ko te hua o tētahi poukapa me te kōaro ko te poukapa tuakiri.

$$\left(\begin{matrix}1&0\\0&1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}2&-3\\3&2\end{matrix}\right))\left(\begin{matrix}4\\6\end{matrix}\right)$$

Whakareatia ngā poukapa kei te taha mauī o te tohu ōrite.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}2&-3\\3&2\end{matrix}\right))\left(\begin{matrix}4\\6\end{matrix}\right)$$

Mō te poukapa 2\times 2 \left(\begin{matrix}a&b\\c&d\end{matrix}\right), ko te \left(\begin{matrix}\frac{d}{ad-bc}&\frac{-b}{ad-bc}\\\frac{-c}{ad-bc}&\frac{a}{ad-bc}\end{matrix}\right) te poukapa kōaro, nō reira ka taea te tuhi anō te whārite poukapa hei rapanga whakarea poukapa.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{2}{2\times 2-\left(-3\times 3\right)}&-\frac{-3}{2\times 2-\left(-3\times 3\right)}\\-\frac{3}{2\times 2-\left(-3\times 3\right)}&\frac{2}{2\times 2-\left(-3\times 3\right)}\end{matrix}\right)\left(\begin{matrix}4\\6\end{matrix}\right)$$

Mahia ngā tātaitanga.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{2}{13}&\frac{3}{13}\\-\frac{3}{13}&\frac{2}{13}\end{matrix}\right)\left(\begin{matrix}4\\6\end{matrix}\right)$$

Whakareatia ngā poukapa.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{2}{13}\times 4+\frac{3}{13}\times 6\\-\frac{3}{13}\times 4+\frac{2}{13}\times 6\end{matrix}\right)$$

Mahia ngā tātaitanga.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}2\\0\end{matrix}\right)$$

Tangohia ngā huānga poukapa x me y.

$$x=2,y=0$$

Ngā Upane e Whakamahi i te Tangohanga

Hei whakaoti mā te tangohanga, ko ngā tau whakarea o tētahi o ngā taurangi me mātua ōrite i ngā whārite e rua kia whakakorehia ai te taurangi ina tangohia tētahi whārite mai i tētahi atu.

$$2x-3y=4,3x+2y=6$$

Kia ōrite ai a 2x me 3x, whakareatia ngā kīanga tau katoa kei ia taha o te whārite tuatahi ki te 3 me ngā kīanga tau katoa kei ia taha o te whārite tuarua ki te 2.

$$3\times 2x+3\left(-3\right)y=3\times 4,2\times 3x+2\times 2y=2\times 6$$

Whakarūnātia.

$$6x-9y=12,6x+4y=12$$

Me tango 6x+4y=12 mai i 6x-9y=12 mā te tango i ngā kīanga tau ōrite i ia taha o te tohu ōrite.

$$6x-6x-9y-4y=12-12$$

Tāpiri 6x ki te -6x. Ka whakakore atu ngā kupu 6x me -6x, ka toe he whārite me tētahi taurangi kotahi ka taea te whakaoti.

$$-9y-4y=12-12$$

Tāpiri -9y ki te -4y.

$$-13y=12-12$$

Tāpiri 12 ki te -12.

$$-13y=0$$

Whakawehea ngā taha e rua ki te -13.

$$y=0$$

Whakaurua te 0 mō y ki 3x+2y=6. I te mea kotahi anake te taurangi kei te whārite i puta, ka taea e koe te whakaoti mō x hāngai tonu.

$$3x=6$$

Whakawehea ngā taha e rua ki te 3.

$$x=2$$

Kua oti te pūnaha te whakatau.

$$x=2,y=0$$