Whakaoti i te {l}{10x^2-3x^3+6^2}{*4}

$$\left. \begin{array} { l } { 10 x ^ { 2 } - 3 x ^ { 3 } + 6 ^ { 2 } } \\ { \times 4 } \end{array} \right.$$

Aromātai

$$144+10x^{2}-3x^{3}$$

Ngā Upane Otinga

Tātaihia te 6 mā te pū o 2, kia riro ko 36.

$$10x^{2}-3x^{3}+36\times 4$$

Whakareatia te 36 ki te 4, ka 144.

$$10x^{2}-3x^{3}+144$$

Kimi Pārōnaki e ai ki x

$$x\left(20-9x\right)$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Tātaihia te 6 mā te pū o 2, kia riro ko 36.

$$\frac{\mathrm{d}}{\mathrm{d}x}(10x^{2}-3x^{3}+36\times 4)$$

Whakareatia te 36 ki te 4, ka 144.

$$\frac{\mathrm{d}}{\mathrm{d}x}(10x^{2}-3x^{3}+144)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$2\times 10x^{2-1}+3\left(-3\right)x^{3-1}$$

Whakareatia 2 ki te 10.

$$20x^{2-1}+3\left(-3\right)x^{3-1}$$

Tango 1 mai i 2.

$$20x^{1}+3\left(-3\right)x^{3-1}$$

Whakareatia 3 ki te -3.

$$20x^{1}-9x^{3-1}$$

Tango 1 mai i 3.

$$20x^{1}-9x^{2}$$

Mō tētahi kupu t, t^{1}=t.

$$20x-9x^{2}$$