Whakaoti i te {l}{1+a+b+c=0}{8+4a+2b+c=0}{27+9a+3b+c=0}

$$\left. \begin{array} { l } { 1 + a + b + c = 0 } \\ { 8 + 4 a + 2 b + c = 0 } \\ { 27 + 9 a + 3 b + c = 0 } \end{array} \right.$$

Whakaoti mō a, b, c

$$a=-6$$

$$b=11$$

$$c=-6$$

Ngā Hipanga Poto E Whakamahi Whakakapinga Ana

Me whakaoti te 1+a+b+c=0 mō a.

$$a=-1-b-c$$

Whakakapia te -1-b-c mō te a i te whārite tuarua me te tuatoru.

$$8+4\left(-1-b-c\right)+2b+c=0 27+9\left(-1-b-c\right)+3b+c=0$$

Me whakaoti ēnei whārite mō b me c takitahi.

$$b=2-\frac{3}{2}c c=\frac{9}{4}-\frac{3}{4}b$$

Whakakapia te 2-\frac{3}{2}c mō te b i te whārite c=\frac{9}{4}-\frac{3}{4}b.

$$c=\frac{9}{4}-\frac{3}{4}\left(2-\frac{3}{2}c\right)$$

Me whakaoti te c=\frac{9}{4}-\frac{3}{4}\left(2-\frac{3}{2}c\right) mō c.

$$c=-6$$

Whakakapia te -6 mō te c i te whārite b=2-\frac{3}{2}c.

$$b=2-\frac{3}{2}\left(-6\right)$$

Tātaitia te b i te b=2-\frac{3}{2}\left(-6\right).

$$b=11$$

Whakakapia te 11 mō te b me te -6 mō c i te whārite a=-1-b-c.

$$a=-1-11-\left(-6\right)$$

Tātaitia te a i te a=-1-11-\left(-6\right).

$$a=-6$$

Kua oti te pūnaha te whakatau.

$$a=-6 b=11 c=-6$$