Whakaoti i te {l}{text{youca.}}{2x_{1}-3x_{2}-x_{3}+6=0}{3x_{1}+4x_{2}+3x_{3}+5=0}{x_{1}+x_{2}+x_{3}+2=0}

$$\left. \begin{array} { l } { \text { youca. } } \\ { 2 x _ { 1 } - 3 x _ { 2 } - x _ { 3 } + 6 = 0 } \\ { 3 x _ { 1 } + 4 x _ { 2 } + 3 x _ { 3 } + 5 = 0 } \\ { x _ { 1 } + x _ { 2 } + x _ { 3 } + 2 = 0 } \end{array} \right.$$

Whakaoti mō x_2, x_3, x_1

$$x_{2}=1$$

$$x_{3}=3$$

$$x_{1}=-6$$

Ngā Hipanga Poto E Whakamahi Whakakapinga Ana

Me whakaoti te -3x_{2}-x_{3}+6=0 mō x_{3}.

$$x_{3}=-3x_{2}+6$$

Whakakapia te -3x_{2}+6 mō te x_{3} i te whārite tuarua me te tuatoru.

$$3x_{1}+4x_{2}+3\left(-3x_{2}+6\right)+5=0 x_{1}+x_{2}-3x_{2}+6+2=0$$

Me whakaoti ēnei whārite mō x_{2} me x_{1} takitahi.

$$x_{2}=\frac{3}{5}x_{1}+\frac{23}{5} x_{1}=-8+2x_{2}$$

Whakakapia te \frac{3}{5}x_{1}+\frac{23}{5} mō te x_{2} i te whārite x_{1}=-8+2x_{2}.

$$x_{1}=-8+2\left(\frac{3}{5}x_{1}+\frac{23}{5}\right)$$

Me whakaoti te x_{1}=-8+2\left(\frac{3}{5}x_{1}+\frac{23}{5}\right) mō x_{1}.

$$x_{1}=-6$$

Whakakapia te -6 mō te x_{1} i te whārite x_{2}=\frac{3}{5}x_{1}+\frac{23}{5}.

$$x_{2}=\frac{3}{5}\left(-6\right)+\frac{23}{5}$$

Tātaitia te x_{2} i te x_{2}=\frac{3}{5}\left(-6\right)+\frac{23}{5}.

$$x_{2}=1$$

Whakakapia te 1 mō te x_{2} i te whārite x_{3}=-3x_{2}+6.

$$x_{3}=-3+6$$

Tātaitia te x_{3} i te x_{3}=-3+6.

$$x_{3}=3$$

Kua oti te pūnaha te whakatau.

$$x_{2}=1 x_{3}=3 x_{1}=-6$$