Whakaoti i te {l}{text{(9)}3-4f=1}{text{10)}d_{8}+6=12}

$$\left. \begin{array} { l } { \text { (9) } 3 - 4 f = 1 } \\ { \text { 10) } d _ { 8 } + 6 = 12 } \end{array} \right.$$

Whakaoti mō f, d_8

$$f=\frac{1}{2}=0.5$$

$$d_{8}=6$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Tangohia te 3 mai i ngā taha e rua.

$$-4f=1-3$$

Tangohia te 3 i te 1, ka -2.

$$-4f=-2$$

Whakawehea ngā taha e rua ki te -4.

$$f=\frac{-2}{-4}$$

Whakahekea te hautanga \frac{-2}{-4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -2.

$$f=\frac{1}{2}$$

Whakaarohia te whārite tuarua. Tangohia te 6 mai i ngā taha e rua.

$$d_{8}=12-6$$

Tangohia te 6 i te 12, ka 6.

$$d_{8}=6$$

Kua oti te pūnaha te whakatau.

$$f=\frac{1}{2} d_{8}=6$$