Whakaoti i te {l}{quad1=a_{1}=a_{2}text{and}a_{n}=a_{n-1}+a_{n-2},n>2}{text{Find}frac{a_{n+1}}{a_{n}},text{for}n=1,2,3,4,5}

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a_{1}=1

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\left. \begin{array} { l } { \quad 1 = a _ { 1 } = a _ { 2 } \text { and } a _ { n } = a _ { n - 1 } + a _ { n - 2 } , n > 2 } \\ { \text { Find } \frac { a _ { n + 1 } } { a _ { n } } , \text { for } n = 1,2,3,4,5 } \end{array} \right.

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

a_{1}=1

Pātaitai

Linear Equation

5 raruraru e ōrite ana ki:

Ngā Raru Ōrite mai i te Rapu Tukutuku

Propositional Logic with rules of inference problem.

https://math.stackexchange.com/questions/676364/propositional-logic-with-rules-of-inference-problem

I'll give a summary "sketch" of one proof approach. I'd suggest you start from the first premise: First check what follows from r\land \lnot s and then what follows when q \land \lnot s. (At ...

How to give a biological interpretation to this phase portrait?

https://biology.stackexchange.com/q/70034

I don't think you missed anything important! You could investigate the cyclic behaviour around the equilibrium. For example, looking at the variable aphid population size can start above its ...

When does a system of equations have no solution?

https://math.stackexchange.com/q/298306

Given a system of linear equations represented by the matrix equation: \mathbf{A}\vec{x}=\vec{b}, there is no unique set of solutions for \det{\mathbf{A}}=0. Therefore, in your case: \begin{bmatrix}-3 & -1 & 2 \\ 0 & -\frac{5}{3} & \frac{10}{3} \\ 0 & 0 & a+2\end{bmatrix}\begin{bmatrix}x \\ y \\ z\end{bmatrix}=\begin{bmatrix}1 \\ \frac{8}{3} \\ b+\frac{6}{5}\end{bmatrix} ...

Runge Kutta method order

https://math.stackexchange.com/questions/1291162/runge-kutta-method-order

Any Runge-Kutta method can be used as a quadrature formula. Just apply it to \frac{dy}{dx} = f(x) so y_{n+1} = y_{n} + h \sum b_i f(c_i). Let's assume that the method is of third order. ...

Multi dimensional multiresolution analysis, designing biorthogonal wavelets.

https://math.stackexchange.com/questions/1661319/multi-dimensional-multiresolution-analysis-designing-biorthogonal-wavelets

If you want to use dyadic dilation for your wavelets, then for n=2, the corresponding matrix equations are \begin{bmatrix} H(z_{1},z_{2})&G_{1}(z_{1},z_{2})&G_{2}(z_{1},z_{2})&G_{3}(z_{1},z_{2})\\ H(-z_{1},z_{2})&G_{1}(-z_{1},z_{2})&G_{2}(-z_{1},z_{2})&G_{3}(-z_{1},z_{2})\\ H(z_{1},-z_{2})&G_{1}(z_{1},-z_{2})&G_{2}(z_{1},-z_{2})&G_{3}(z_{1},-z_{2})\\ H(-z_{1},-z_{2})&G_{1}(-z_{1},-z_{2})&G_{2}(-z_{1},-z_{2})&G_{3}(-z_{1},-z_{2}) \end{bmatrix} \times\begin{bmatrix} \tilde{H}(z_{1},z_{2})&\tilde{H}(-z_{1},z_{2})&\tilde{H}(z_{1},-z_{2})&\tilde{H}(-z_{1},-z_{2})\\ \tilde{G}_{1}(z_{1},z_{2})&\tilde{G}_{1}(-z_{1},z_{2})&\tilde{G}_{1}(z_{1},-z_{2})&\tilde{G}_{1}(-z_{1},-z_{2})\\ \tilde{G}_{2}(z_{1},z_{2})&\tilde{G}_{2}(-z_{1},z_{2})&\tilde{G}_{2}(z_{1},-z_{2})&\tilde{G}_{2}(-z_{1},-z_{2})\\ \tilde{G}_{3}(z_{1},z_{2})&\tilde{G}_{3}(-z_{1},z_{2})&\tilde{G}_{3}(z_{1},-z_{2})&\tilde{G}_{3}(-z_{1},-z_{2}) \end{bmatrix}=4I, ...

How to prove my matrix's powers?

https://math.stackexchange.com/questions/2201465/how-to-prove-my-matrixs-powers

Well, let T = \begin{pmatrix}A & 0 \\ B & I\end{pmatrix}, \quad A = \begin{pmatrix}0 & 2 \\ \frac{1}{2} & 0\end{pmatrix}, \quad B = \begin{pmatrix}1 & 0 \\ 1 & 1\end{pmatrix}, and I is a unit ...

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a_{1}=1

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

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whārite tapawhā

{ x } ^ { 2 } - 4 x - 5 = 0

Āhuahanga

4 \sin \theta \cos \theta = 2 \sin \theta

\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]

whārite Simultaneous

\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.

Whakarerekētanga

\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }

Whakaurunga

\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x

Ngā Tepe

\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}

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