Whakaoti i te {l}{2x+3/3y-2=1}{x(2y+2)-2y(x+3)=2x+1}

$$\left. \begin{array} { l } { \frac { 2 x + 3 } { 3 y - 2 } = 1 } \\ { x ( 2 y + 2 ) - 2 y ( x + 3 ) = 2 x + 1 } \end{array} \right.$$

Whakaoti mō x, y

$$x = -\frac{11}{4} = -2\frac{3}{4} = -2.75$$

$$y=-\frac{1}{6}\approx -0.166666667$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Tē taea kia ōrite te tāupe y ki \frac{2}{3} nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te 3y-2.

$$2x+3=3y-2$$

Tangohia te 3y mai i ngā taha e rua.

$$2x+3-3y=-2$$

Tangohia te 3 mai i ngā taha e rua.

$$2x-3y=-2-3$$

Tangohia te 3 i te -2, ka -5.

$$2x-3y=-5$$

Whakaarohia te whārite tuarua. Whakamahia te āhuatanga tohatoha hei whakarea te x ki te 2y+2.

$$2xy+2x-2y\left(x+3\right)=2x+1$$

Tangohia te 2x mai i ngā taha e rua.

$$2xy+2x-2y\left(x+3\right)-2x=1$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2y ki te x+3.

$$2xy+2x-2yx-6y-2x=1$$

Pahekotia te 2xy me -2yx, ka 0.

$$2x-6y-2x=1$$

Pahekotia te 2x me -2x, ka 0.

$$-6y=1$$

Whakawehea ngā taha e rua ki te -6.

$$y=-\frac{1}{6}$$

Whakaarohia te whārite tuatahi. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$2x-3\left(-\frac{1}{6}\right)=-5$$

Whakareatia te -3 ki te -\frac{1}{6}, ka \frac{1}{2}.

$$2x+\frac{1}{2}=-5$$

Tangohia te \frac{1}{2} mai i ngā taha e rua.

$$2x=-5-\frac{1}{2}$$

Tangohia te \frac{1}{2} i te -5, ka -\frac{11}{2}.

$$2x=-\frac{11}{2}$$

Whakawehea ngā taha e rua ki te 2.

$$x=\frac{-\frac{11}{2}}{2}$$

Tuhia te \frac{-\frac{11}{2}}{2} hei hautanga kotahi.

$$x=\frac{-11}{2\times 2}$$

Whakareatia te 2 ki te 2, ka 4.

$$x=\frac{-11}{4}$$

Ka taea te hautanga \frac{-11}{4} te tuhi anō ko -\frac{11}{4} mā te tango i te tohu tōraro.

$$x=-\frac{11}{4}$$

Kua oti te pūnaha te whakatau.

$$x=-\frac{11}{4} y=-\frac{1}{6}$$