Whakaoti i te {l}{z=7+i}{a={(z^2+1z^2)}^2}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { z = 7 + i }\\ { a = {(z ^ {2} + 1 z ^ {2})} ^ {2} }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Whakaoti mō z, a, b, c, d

$$d=8432+5376i$$

Ngā Upane Otinga

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=\left(\left(7+i\right)^{2}+1\left(7+i\right)^{2}\right)^{2}$$

Tātaihia te 7+i mā te pū o 2, kia riro ko 48+14i.

$$a=\left(48+14i+1\left(7+i\right)^{2}\right)^{2}$$

Tātaihia te 7+i mā te pū o 2, kia riro ko 48+14i.

$$a=\left(48+14i+1\left(48+14i\right)\right)^{2}$$

Whakareatia te 1 ki te 48+14i, ka 48+14i.

$$a=\left(48+14i+\left(48+14i\right)\right)^{2}$$

Tāpirihia te 48+14i ki te 48+14i, ka 96+28i.

$$a=\left(96+28i\right)^{2}$$

Tātaihia te 96+28i mā te pū o 2, kia riro ko 8432+5376i.

$$a=8432+5376i$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=8432+5376i$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=8432+5376i$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$d=8432+5376i$$

Kua oti te pūnaha te whakatau.

$$z=7+i a=8432+5376i b=8432+5376i c=8432+5376i d=8432+5376i$$